Describe the graph of the equation: r= 3ti – 6j + (1- 31)k. [Choose the correct answer.] The equation is a line in 3-space through the point (0, – 6) and parallel to the vector 3i 3k. O The equation is a line in 3-space through the point (3) and parallel to the vector - 6j - k. O The equation is a line in 3-space through the point (0, - 6) and perpendicular to the vector 3i + 3k. O The equation is a helix in 3-space containing the point (0, - 6) and above a circle with radius 6.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 17RE
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Describe the graph of the equation: r= 3ti – 6j + (1- 31)k. [Choose the correct answer.]
The equation is a line in 3-space through the point (0, – 6) and parallel to the vector 3i 3k.
O The equation is a line in 3-space through the point (3) and parallel to the vector -6j - k.
O The equation is a line in 3-space through the point (0, - 6) and perpendicular to the vector 31+ 3k.
O The equation is a helix in 3-space containing the point (0, - 6) and above a circle with radius 6.
Transcribed Image Text:Describe the graph of the equation: r= 3ti – 6j + (1- 31)k. [Choose the correct answer.] The equation is a line in 3-space through the point (0, – 6) and parallel to the vector 3i 3k. O The equation is a line in 3-space through the point (3) and parallel to the vector -6j - k. O The equation is a line in 3-space through the point (0, - 6) and perpendicular to the vector 31+ 3k. O The equation is a helix in 3-space containing the point (0, - 6) and above a circle with radius 6.
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