Derive the difference equation given the block diagram. Supply the missing term y yln]= a1 x[n-1]+ bi y[n-1]

For the system given constant coefficient difference equation: ylnl-2.5yln-1]+yln-2]=2xLn]+0.5x[n-1] Draw the block diagram in type-1 and type-2 format.

Remember, binary subtraction is implemented by adding the 2's complement value of the subtrahend. In the following predictions, be sure to negate the subtrahends. Set #1 SUB Set #2 SUB A= 7 B= 2 A= B= S= Cout= Overflow Set #3: SUB A= B= 1 3 S= Cout= -8 4 Overflow A3 B3 S3 A₂ S3 A₁ B₂ B₁ B3 B₂ Ao Bo S₂ S₁ So A3 A₂ A₁ Ao B₁1 Bo S2 S₁ So S= Cout= Overflow Set #4 SUB A= -6 B= -5 S= Cout= Overflow A3 B3 A3 B3 A₂ S3 B₂ A₁ S3 S₂ S₁ So A₂ В1 Ao Bo B₂ В1 A₁ Ao Bo S₂ S₁ So

This is a practice problem I am having a little difficulty with understanding. Thank you for the help.

1-14. (a) Write the Vo1 expression by inspection and solve for Vo1 using a voltage divider. (b) Write the Vo2 expression by inspection and solve for Vo2 using a voltage divider. Vo2 3 V 50 k 125 k 75 k 80 k Vol 125 k

How do I get the eight BIT Adder Subtracter Module (the square one) on Quartus 2?

Use K-map to minimize the following SOP expression: Q1) A'B'C'D'E' + A'B'CD'E' + A'BCD'E' + A'BC'D'E' + A'B'C'D'E + A'BCD'E + A'BCDE + AB'C'D'E' + AB'C'D'E + ABCD'E + ABCDE + AB'CDE Q2) F (A,B,C,D,E) = Σm ( 0, 2, 5, 7, 8, 10, 16, 21, 23, 24, 27, 31) === Q3) F (A,B,C,D,E) = m ( 0, 2, 4, 6, 9, 11, 13, 15, 16, 17, 18, 19, 25, 27, 29, 31 ) =========

In R/2nR DAC, the maximum input resistor to be used is Rmin*2^(n-1) where n is the number of bits. Rmin*(2^n)-1 where n is the number of bits. Rmin*2^n wheren is the number of bits. Rmin*[(2^n)-1] where n is the number of bits.