dentist uses a mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the tooth is formed 13.0 cm behind the mirror. (a) Determine the mirror's radius of curvature. cm (b) Determine the magnification of the image.

dentist uses a mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the tooth is formed 13.0 cm behind the mirror. (a) Determine the mirror's radius of curvature. cm (b) Determine the magnification of the image.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter26: Image Formation By Mirrors And Lenses

Section: Chapter Questions

Problem 67P: The disk of the Sun subtends an angle of 0.533 at the Earth. What are (a) the position and (b) the...

See similar textbooks

Related questions

Q: A convex spherical mirror, whose focal length has a magnitude of 29.0 cm, is to form an image 9.0 cm…

Q: The image behind a convex mirror (radius of curvature = 90.0 cm) is located 28.0 cm from the mirror.…

Q: A technician wishes to form a virtual image of a gemstone at a distance of 18.1 cm behind a concave…

Q: A dentist uses a mirror to examine a tooth that is 1.25 cm in front of the mirror. The image of the…

A: (a) By the mirror formula, 1/u + 1/v = 2/R R = 2uv/(u+v) R = (2x1.25x(-10)) / (1.25-10) R = 2.857…

Q: VARIANT 2 1. A converging lens of focal length 15.0 cm forms an image of each of two objects placed…

Q: A doctor wishes to inspect a patient's tooth with a magnifying mirror. She places the mirror 1.00 cm…

A: The mirror equation is given as 1f=1v+1uhere v is image distance u is object distanceUsing sign…

Q: A convex mirror with a radius of curvature of -30.0 cm is used to form an image of an arrow that is…

Q: An object is located at a distances 14 (cm] in front of a mirror having a focal length of f = 20…

A: Here it is given that focal length is f=20cm. as we can see this focal length is positive and…

Q: When an object is placed 38.5 cm in front of a convex spherical mirror, a virtual image forms 12.5…

Q: A dentist uses a mirror to examine a tooth. The tooth is 1.14 cm in front of the mirror, and the…

Q: An object 2.00 cm high is placed 12.3 cm in front of a convex mirror with radius of curvature of…

Q: A virtual image is formed 18.5 cm from a concave mirror having a radius of curvature of 35.5 cm. (a)…

Q: A dental hygienist uses a small concave mirror to look at the back of a patient's tooth. If the…

A: The magnification (m) produced by the mirror is defined as the ratio of the height of the image (hi)…

Q: onvex mirror with a radius of curvature of -26.0 cm is used to form an image of an arrow that is…

Concept explainers

Applications Of Reflection Of Light

When a light ray (termed as the incident ray) hits a surface and bounces back (forms a reflected ray), the process of reflection of light has taken place.

Sign Convention for Mirrors

A mirror is made of glass that is coated with a metal amalgam on one side due to which the light ray incident on the surface undergoes reflection and not refraction.

Question

100%

A dentist uses a mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the tooth is formed 13.0 cm behind the
mirror.
(a) Determine the mirror's radius of curvature.
cm
(b) Determine the magnification of the image.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A convex mirror with a radius of curvature of 25.0 cm is used to form an image of an arrow that is 10.0 cm away from the mirror. If the arrow is 2.00 cm tall and inverted (pointing below the optical axis), what is the height of the arrows image?
The disk of the Sun subtends an angle of 0.533 at the Earth. What are (a) the position and (b) the diameter of the solar image formed by a concave spherical mirror with a radius of curvature of magnitude 3.00 m?
A lamp of height S cm is placed 40 cm in front of a converging lens of focal length 20 cm. There is a plane mirror 15 cm behind the lens. Where would you find the image when you look in the mirror?
The magnification of an upright image that is 34.0 cm away from its object is 0.400. What type of lens is used to form the image, and what is its focal length?
What is the magnification of a magnifying lens with a focal length of 10 cm if it is held 3.0 cm from the eye and the object is 12 cm from the eye?
Suppose a man stands in front of a mirror as shown in Figure 25.50. His eyes are 1.65 m above the floor, and the top of his head is 0.13 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet. How is this distance related to the man’s height? Figure 25.50 A full-length mirror is one in which you can see all of yourself. It need not be as big as you, and its size is independent of your distance from it.
You view an object by holding a 2.5 cm-focal length magnifying glass 10 cm away from it. How far from your eye should you hold the magnifying glass to obtain a magnification of 10 ?
Show that the magnification of a thin lens is given by M = di/do (Eq. 38.6). Hint: Follow the derivation of the lens makers equation (page 1233) and start with a thick lens.
In Figures CQ36.11a and CQ36.11b, which glasses correct nearsightedness and which correct farsightedness?
Figure P38.43 shows a concave meniscus lens. If |r1| = 8.50 cm and |r2| = 6.50 cm, find the focal length and determine whether the lens is converging or diverging. The lens is made of glass with index of refraction n = 1.55. CHECK and THINK: How do your answers change if the object is placed on the right side of the lens? FIGURE P38.43
In Figure P26.38, a thin converging lens of focal length 14.0 cm forms an image of the square abcd, which is hc = hb = 10.0 cm high and lies between distances of pd = 20.0 cm and pa = 30.0 cm from the lens. Let a, b, c, and d represent the respective corners of the image. Let qa represent the image distance for points a and b, qd represent the image distance for points c and d, hb represent the distance from point b to the axis, and hc represent the height of c. (a) Find qa, qd, hb, and hc. (b) Make a sketch of the image. (c) The area of the object is 100 cm2. By carrying out the following steps, you will evaluate the area of the image. Let q represent the image distance of any point between a and d, for which the object distance is p. Let h represent the distance from the axis to the point at the edge of the image between b and c at image distance q. Demonstrate that h=10.0q(114.01q) where h and q are in centimeters. (d) Explain why the geometric area of the image is given by qaqdhdq (e) Carry out the integration to find the area of the image. Figure P26.38
(a) A concave spherical mirror forms ail inverted image different in size from the object by a factor a 1. I'he distance between object and image is d. Find the local length of the mirror, (b) What If? Suppose the mirror is convex, an upright image is formed, and a 1. Determine the focal length of the minor.