deducted from points of correct answers. LINE 1 LINE 2 LINE 3 LINE 4 LINE S LINE G LINE 7 LINE 8 LINE 9 LINE 10 LINE I LINE 12 LINE 13 LINE LINE S v² dx + x(x+x) dx = 0 let x= x= ₁ y² (yd2 + zdv) + xz (vz+x) dx = 0 v² (vdz + adv) + √²2 (2+1) dx = 0 vd2 +2dv + (2²+1) dy = 0 vd2 + (2²+22) dy = 0 dz + dy=0 2² +22 In - e but I - 2422 1 L 2² +22 Y₂) dz + dv =) 2+2 ½/₂ + = 0 2 1/2 In (2) - 1/2 In (2+2) + In(v) = C In (2) In (2+2) + In (v²) = C v² 2+2 v/x+2 v²x x + 2y с = C e 2+2 √² (V/X) = C dx = xd₂ + zdy (2+2) Yz 2 = G А 2 1₂ 2+2 + B 2+2

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 5E
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NUMBER 17

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Topic: Differential Equations (Engineering)
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Identify three (3) lines in error on the
solution of the given differential equation.
The absence of an integral sign is not
considered an error. Please be extra
careful in selecting correct answers.
Points from incorrect answers will be
deducted from points of correct answers.
v² dx + x(x + x) dx = 0
LINE 1
let x= x=
LINE 2 y² (yd2 + zdv) +
LINE 3
LINE 4
LINE 5
LINE G
LINE 7
LINE 8
LINE 9
LINE 10
LINE I
LINE 12
LINE 13
LINE
LINE S
dx = xd₂ + zdy
x2 (√2 + x) dx = 0
v² (vdz + zdv) + √²2 (2+1) dx = 0
vd2 + zdv + (2²+1) dy = 0
vd2 +(2+22) dy = 0
dz
d² + y = 0
dy
2² +22
In
but,
e
22422
1
√²
2+2 e
C
(2+2)
Yz
с
2+2
V² (V/X) = C
VX+2
v²x
= G
x+2y
=
2² +22
2
2+2) dz + dv² = 0²
V
(1/₂
+
2
1/2 In (2) - 1/2 In (2+2) + In[v) = C
In (2)
In (2+2) + In (v²) = C
=
-
А
12
2+2
+
B
2+2
Transcribed Image Text:Identify three (3) lines in error on the solution of the given differential equation. The absence of an integral sign is not considered an error. Please be extra careful in selecting correct answers. Points from incorrect answers will be deducted from points of correct answers. v² dx + x(x + x) dx = 0 LINE 1 let x= x= LINE 2 y² (yd2 + zdv) + LINE 3 LINE 4 LINE 5 LINE G LINE 7 LINE 8 LINE 9 LINE 10 LINE I LINE 12 LINE 13 LINE LINE S dx = xd₂ + zdy x2 (√2 + x) dx = 0 v² (vdz + zdv) + √²2 (2+1) dx = 0 vd2 + zdv + (2²+1) dy = 0 vd2 +(2+22) dy = 0 dz d² + y = 0 dy 2² +22 In but, e 22422 1 √² 2+2 e C (2+2) Yz с 2+2 V² (V/X) = C VX+2 v²x = G x+2y = 2² +22 2 2+2) dz + dv² = 0² V (1/₂ + 2 1/2 In (2) - 1/2 In (2+2) + In[v) = C In (2) In (2+2) + In (v²) = C = - А 12 2+2 + B 2+2
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