decides to implement a reading program. It is to be administered to the bottom 10% of the students in the district, based on the scores on a reading achievement exam. If the average score for the students in the district is 118.0, find the cutoff score that will make a student eligible for the program. The standard deviation is 22. Assume the variable is normally distributed. Round z-value calculations to a decimal places and the final answer to the nearest whole number. Cutoff score=

Draw by hand or in Excel fully labelled curves on a common scale to represent two sets of scores where: b. Mean = 50, Standard Deviation = 2, Mean = 50, Standard Deviation = 5. CUA

Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees and standard deviation of 1.00degreesC. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to Upper P 90, the 90th percentile. This is the temperature reading separating the bottom 90% from the top 10%.

Assume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15. Find P25​, which is the IQ score separating the bottom 25​% from the top 75​%. Round your answer to nearest tenth.

Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Click the icon to view the data table of IQ scores. a. Use a 0.05 significance level to test the claim that the mean IQ scores for subjects with medium lead levels is higher than the mean for subjects with high lead levels. What are the null and alternative hypotheses? Assume that population 1 consists of subjects with medium lead levels and population 2 consists of subjects with high lead levels. X A. Ho: H₁ H₂ H₁ H₁ H₂ c. Ho: M₁ = H₂ H₁: H₁ H₂ The test statistic is 0.56. (Round to two decimal places as needed.) The P-value is (Round to three decimal…

Students must have GPAs in the top 7.5% of the school to be accepted into the honour society. When the average GPA is 2.92 with the standard deviation of 0.29, what GPA do you have to have to be accepted? Show all your work. Round off to 100th.

The mean score on the ACT test was 19.3 and the standard deviation was 5.4. The distributions of scores was approximately bell-shaped. Compute the z-score for an ACT test score of 15. Write only a number as your answer. Round your answer to two decimal places (for example: 3.15).

Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table Click to view page 2 of the table. The indicated IQ score, x, is (Round to one decimal place as needed.) X 0.8 N

Help me find which A,B,C, or D is the correct answer to the last part please. The brain volumes ​(cm3​) of 50 brains vary from a low of 904 cm3 to a high of 1490 cm3. Use the range rule of thumb to estimate the standard deviation s and compare the result to the exact standard deviation of 191.4 cm3​, assuming the estimate is accurate if it is within 15 cm3. The estimated standard deviation is 146.5 cm3.     A. The approximation is not accurate because the error of the range rule of​ thumb's approximation is greater than 15 cm3.   B. The approximation is not accurate because the error of the range rule of​ thumb's approximation is less than 15 cm3.   C. The approximation is accurate because the error of the range rule of​ thumb's approximation is greater than 15 cm3.   D. The approximation is accurate because the error of the range rule of​ thumb's approximation is less than 15 cm3.

Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P50, the 50-percentile. This is the temperature reading separating the bottom 50% from the top 50%. Round to 3 decimal places.