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Data Set Exp.5 Use the following data to determine the mass percent of the active ingredient in Aspirin a) Preparation of solutions: volume of salicylic acid volume of FECL3 solution SA1 1ml 9ml SA2 3.5ml 6.5ml SA3 6.5ml 3.5ml SA4 1ml 9ml The concentration of salicylic acid= 0.000725M b) Preparation of “STOCK ASA UNKNOWN" The mass of aspirin= 0.135 g The volume of stock solution of aspirin= 100ml The dilution factor for the stock solution= 50/2 Molar mass of SAS = 180.157 g/mole c) Measurements of Absorbance: Solution Absorbance SA1 0.154 SA2 0.524 SA3 0.789 SA4 0.989 The unknown sample 0.259

Data Set Exp.5 Use the following data to determine the mass percent of the active ingredient in Aspirin a) Preparation of solutions: volume of salicylic acid volume of FECL3 solution SA1 1ml 9ml SA2 3.5ml 6.5ml SA3 6.5ml 3.5ml SA4 1ml 9ml The concentration of salicylic acid= 0.000725M b) Preparation of “STOCK ASA UNKNOWN" The mass of aspirin= 0.135 g The volume of stock solution of aspirin= 100ml The dilution factor for the stock solution= 50/2 Molar mass of SAS = 180.157 g/mole c) Measurements of Absorbance: Solution Absorbance SA1 0.154 SA2 0.524 SA3 0.789 SA4 0.989 The unknown sample 0.259

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Data Set Exp.5 Use the following data to determine the mass percent of the active ingredient in Aspirin a) Preparation of solutions: volume of salicylic acid volume of FECL3 solution SA1 1ml 9ml SA2 3.5ml 6.5ml SA3 6.5ml 3.5ml SA4 1ml 9ml The concentration of salicylic acid= 0.000725M b) Preparation of "STOCK ASA UNKNOWN" The mass of aspirin= 0.135 g The volume of stock solution of aspirin= 100ml The dilution factor for the stock solution= 50/2 Molar mass of SAS = 180.157 g/mole c) Measurements of Absorbance: Solution Absorbance SA1 0.154 SA2 0.524 SA3 0.789 SA4 0.989 The unknown sample 0.259
Transcribed Image Text:Data Set Exp.5 Use the following data to determine the mass percent of the active ingredient in Aspirin a) Preparation of solutions: volume of salicylic acid volume of FECL3 solution SA1 1ml 9ml SA2 3.5ml 6.5ml SA3 6.5ml 3.5ml SA4 1ml 9ml The concentration of salicylic acid= 0.000725M b) Preparation of "STOCK ASA UNKNOWN" The mass of aspirin= 0.135 g The volume of stock solution of aspirin= 100ml The dilution factor for the stock solution= 50/2 Molar mass of SAS = 180.157 g/mole c) Measurements of Absorbance: Solution Absorbance SA1 0.154 SA2 0.524 SA3 0.789 SA4 0.989 The unknown sample 0.259
A) Standard solution and Beer's law calibration curve 1-Fill in the following table : Concentration For S.1 M¸ x V = M, x V 0.000725 x 1.0ml = M, x 10.0ml Solution Absorbance Concentration S. 1 S.2 S.3 S.4 ASA of unknown 666666666 2- Plot a graph of Absorbance vs. conc mol / L absorbance Absorbance vs. Concentration 1.6 1.4 1.2 1 0.8 OY-Values 0.6 0.4 0.2 6. 10 conc 104 mol/ L B) Analvsis of unknown aspirin tablet 1. Mass of aspirin tablet = g 2. Concentration of ASA unknown from calibration curve mol / L 3.. Conc of Stock ASA unknown = 50 mL / 1.5 mL (D.F) x Conc of ASA unknown mol / L 4. Moles of ASA in 100 mL solution = Conc of Stock ASA unknown x 0.1 L= moles 5.Mass of ASA = moles ASA x Molar Mass ASA (180 g/ mol) = 6. % of ASA in aspirin Mass of ASA / Mass of aspirin tablet x100 = %3D
Transcribed Image Text:A) Standard solution and Beer's law calibration curve 1-Fill in the following table : Concentration For S.1 M¸ x V = M, x V 0.000725 x 1.0ml = M, x 10.0ml Solution Absorbance Concentration S. 1 S.2 S.3 S.4 ASA of unknown 666666666 2- Plot a graph of Absorbance vs. conc mol / L absorbance Absorbance vs. Concentration 1.6 1.4 1.2 1 0.8 OY-Values 0.6 0.4 0.2 6. 10 conc 104 mol/ L B) Analvsis of unknown aspirin tablet 1. Mass of aspirin tablet = g 2. Concentration of ASA unknown from calibration curve mol / L 3.. Conc of Stock ASA unknown = 50 mL / 1.5 mL (D.F) x Conc of ASA unknown mol / L 4. Moles of ASA in 100 mL solution = Conc of Stock ASA unknown x 0.1 L= moles 5.Mass of ASA = moles ASA x Molar Mass ASA (180 g/ mol) = 6. % of ASA in aspirin Mass of ASA / Mass of aspirin tablet x100 = %3D
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