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Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Can you help me on the part that says change each q to delta h? The data is on the top of the page

Transcribed Image Text:Data and Calculations
Fill in the following data from when you performed this lab. Attach the printed graphs from the
temperature probes to this data sheet when you submit this report. Each person should submit an
individual report with attached graphs.
Trial 4
Trial 1
Trial 3
Trial 2
Mass of Mg/MgO
0.344 0.398 0.1520 D.115
Initial Temperature*
20.6°c
20.4°c 20.7°C
23.5°C
20. 3°C
Final Temperature*
24. 0c
36.2°C
Change in Temp.
2.80c
_18°८ ।
Calculations:
1. For each of your trials determine the heat liberated. Assume the HCl solution in the calorimeter
has a density of 100 g/mL and that the calorimeter loses a negligible amount of heat. (The specific
heat of the solution can be assumed to be the same as water, 4.184 J/g.°C.) Show work neatly for
credit.
mass x specific heat x At
Trial4
Trial1
Trial 2
Triai3
(.1154)4.180H
9(.9444) (4.184) (7.9) 1:13997) (4.184) (18) a-1520) (4.104) (2.8)
8.81
2- 12.98
9-29.5KJ
19.5k 20KT
8.81KJ
12.98KJ
=(kilojoules)
Change eachq to AH with the appropriate sign. Remember that enthalpy has been gained by the
water, therefore, enthalpy has been lost by the reaction system.
AH (kilojoules)
AH-9
43

Transcribed Image Text:Calculations:
1. For each of your trials determine the heat liberated. Assume the HC1 solution in the calorimeter
heat of the solution can be assumed to be the same as water, 4.184 J/g.°C.) Show work neatly for
has a density of 00 g/mL and that the calorimeter loses a negligible amount of heat. (The specific
credit.
=mass x specific heat x At
Triai1
Trial4
Trial 2
Tria13
(1754)4.1840
9(9944) (4.184) (17.9) 1-(.3987) (4.184) (18) C7520) (4.104) (2.0) q
2- 12.98
9-29.5KJ
-8,81
q= (kilojoules)
29.5kJ
20KT
8.81KJ
12.99KJ
Change each q to AH with the appropriate sign. Remember that enthalpy has been gained by the
water, therefore, enthalpy has been lost by the reaction system.
AH=(kilojoules)
1
AH-2
43
Expert Solution
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