D9.3. Find the amplitude of the displacement current density: (a) adjacent to an automobile antenna where the magnetic field intensity of an FM signal is H, = 0.15 cos[3.12(3×10*t – y)] A/m; (b) in the air space at a point within a large power distribution transformer where B = 0.8 cos[1.257x10(3×10*t- x)]a, T; (c) within a large, oil-filled power capacitor where ɛ, = 5 and E = 0.9 cos[1.257 × 10^(3 × 10°t – zV5)]a. MV/m; (d) in a metallic conductor at 60 Hz, if ɛ = E, , µ = lo, o = 5.8×107 S/m, and J = sin(377t –117.1z)a, MA/m?. Ans. 0.468 A/m²; 0.800 A/m²; 0.0150 A/m²; 57.6 pA/m?

Delmar's Standard Textbook Of Electricity
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ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter14: Basic Trigonometry And Vectors
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D9.3. Find the amplitude of the displacement current density: (a) adjacent
to an automobile antenna where the magnetic field intensity of an FM
signal is H, = 0.15 cos[3.12(3×10*t – y)] A/m; (b) in the air space at a
point within a large power distribution transformer where B = 0.8
cos[1.257×10(3×10*t- x)]a, T; (c) within a large, oil-filled power
capacitor where ɛ, = 5 and E = 0.9 cos[1.257 × 10^(3 × 10°t – zV5)]a.
MV/m; (d) in a metallic conductor at 60 Hz, if ɛ = ɛ, , µ = lo, o = 5.8×107
S/m, and J = sin(377t –117.1z)a, MA/m².
Ans. 0.468 A/m²; 0.800 A/m²; 0.0150 A/m²; 57.6 pA/m?
Transcribed Image Text:D9.3. Find the amplitude of the displacement current density: (a) adjacent to an automobile antenna where the magnetic field intensity of an FM signal is H, = 0.15 cos[3.12(3×10*t – y)] A/m; (b) in the air space at a point within a large power distribution transformer where B = 0.8 cos[1.257×10(3×10*t- x)]a, T; (c) within a large, oil-filled power capacitor where ɛ, = 5 and E = 0.9 cos[1.257 × 10^(3 × 10°t – zV5)]a. MV/m; (d) in a metallic conductor at 60 Hz, if ɛ = ɛ, , µ = lo, o = 5.8×107 S/m, and J = sin(377t –117.1z)a, MA/m². Ans. 0.468 A/m²; 0.800 A/m²; 0.0150 A/m²; 57.6 pA/m?
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