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answer for (d) and (e) please 

2. If you very close to the surface on a conductor it will look flat. Just as the Earth appears flat to us because we are on the surface. We want to find the electric field at E a point P just outside the conductor. Assume the conducting surface near P has a positive charge per area n. We draw a Gaussian cylinder of radius R and height 2h cutting through the surface. h +n а. What is the flux through the curved portion of the Gaussian surface? Write the answer in terms of the Conductor unknown electric field E, R and/or h. b. What is the flux through the bottom endcap? What is the flux through the top endcap? С. d. Write the charge enclosed by the Gaussian surface in terms of n, R and/or h? Use Gauss's law to find the electric field just outside the conductor. е.
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Transcribed Image Text:2. If you very close to the surface on a conductor it will look flat. Just as the Earth appears flat to us because we are on the surface. We want to find the electric field at E a point P just outside the conductor. Assume the conducting surface near P has a positive charge per area n. We draw a Gaussian cylinder of radius R and height 2h cutting through the surface. h +n а. What is the flux through the curved portion of the Gaussian surface? Write the answer in terms of the Conductor unknown electric field E, R and/or h. b. What is the flux through the bottom endcap? What is the flux through the top endcap? С. d. Write the charge enclosed by the Gaussian surface in terms of n, R and/or h? Use Gauss's law to find the electric field just outside the conductor. е.
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Step 1

Gauss's Law

The surface integral of the electric field over a closed surface is equal to 1εo times the total charge enclosed by the surface.

∮SE→.dS→=qencεo

 

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