MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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**Excerpt: Student Performance Evaluation Using Z-Scores**

**Grading on a Curve: Statistical Evaluation**

If a professor grades on a curve, which might involve assigning A's to the top 10% of the class regardless of raw scores, we must determine whether a student is better off with a particular grade in two different scenarios using statistical analysis.

**Scenario Analysis:**
- A student has two options: 
  - Grade of 97 on an exam with a mean of 79 and a standard deviation of 9.
  - Grade of 64 on a different exam where the mean is 61 and the standard deviation is 3.

**Statistical Justification:**

The student is better off with a grade of 97 on the exam with a mean of 79 and a standard deviation of 9 because the Z value for the grade of 97 is 2.00. Comparatively, the Z value for the grade of 64 on the different exam is also 2.00. Hence, in terms of statistical performance relative to peers, both grades are equivalent, yielding a Z score of 2.00. However, considering the context of grading on a curve, the higher raw score (97) can offer better prospects for achieving top-tier graded recognition (e.g., being in the top 10%) especially in a curve-based grade distribution.

*(Note: All calculations are rounded to two decimal places as needed.)*
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Transcribed Image Text:**Excerpt: Student Performance Evaluation Using Z-Scores** **Grading on a Curve: Statistical Evaluation** If a professor grades on a curve, which might involve assigning A's to the top 10% of the class regardless of raw scores, we must determine whether a student is better off with a particular grade in two different scenarios using statistical analysis. **Scenario Analysis:** - A student has two options: - Grade of 97 on an exam with a mean of 79 and a standard deviation of 9. - Grade of 64 on a different exam where the mean is 61 and the standard deviation is 3. **Statistical Justification:** The student is better off with a grade of 97 on the exam with a mean of 79 and a standard deviation of 9 because the Z value for the grade of 97 is 2.00. Comparatively, the Z value for the grade of 64 on the different exam is also 2.00. Hence, in terms of statistical performance relative to peers, both grades are equivalent, yielding a Z score of 2.00. However, considering the context of grading on a curve, the higher raw score (97) can offer better prospects for achieving top-tier graded recognition (e.g., being in the top 10%) especially in a curve-based grade distribution. *(Note: All calculations are rounded to two decimal places as needed.)*
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