Related questions
Concept explainers
PLEASE ANSWER (d) ONLY. a-c have been answered.
Suppose a dresser drawer has blue shirts, yellow shirts, red shirts, and green shirts so that if a shirt is pulled from the drawer at random, each color has an equal chance of being drawn. P(Green) = P(Blue) = P(Red) = P(Yellow) = ¼. Complete parts (a) – (d) to create a
(a) List each possible outcomefor the colors of the shirts if two shirts are drawn randomly from the drawer.
Green, Blue, / Green, Red, / Green, Yellow, / Green, Green
Blue, Green / Blue, Blue / Blue, Red / Blue, Yellow
Red, Green / Red, Blue / Red, Red / Red, Yellow
Yellow, Green / Yellow, Blue / Yellow, Red / Yellow, Yellow
(b) List the possible events for the number of yellow shirtsif two shirts are drawn randomly from the drawer.
Green, Yellow / Blue, Yellow / Red, Yellow
Yellow, Yellow
(c) Find the probability of each
P (X=L) = 3/Total Outcomes
P (X=L) = 3/16
P (X=2) = L/16
(d) Make a table that displays each event from (b) and the corresponding probability from (a). This is a probability distribution for the number of yellow shirts drawn when two shirts are randomly pulled from the drawer.
Step by stepSolved in 2 steps
- Ben buys a bag of cookies that contains 8 chocolate chip cookies, 9 peanut butter cookies, 7 sugar cookies and 6 oatmeal cookies. What is the probability that Ben randomly selects a peanut butter cookie from the bag, eats it, then randomly selects a sugar cookie? Probability = (Round your answer to 4 decimal places.)arrow_forwardBased on a survey, assume that 33% of consumers are comfortable having drones deliver their purchases. Suppose we want to find the probability that when six consumers are randomly selected, exactly three of them are comfortable with the drones. What is wrong with using the multiplication rule to find the probability of getting three consumers comfortable with drones followed by three consumers not comfortable, as in this calculation: (0.33)(0.33)(0.33)(0.67)(0.67)(0.67) = 0.0108? Choose the correct answer below. A. The event that a consumer is comfortable with drones is not mutually exclusive with the event that a consumer is not comfortable with drones. B. The probability of the second consumer being comfortable with drones cannot be treated as being independent of the probability of the first consumer being comfortable with drones. O C. There are other arrangements consisting of three consumers who are comfortable and three who are not. The probabilities corresponding to those other…arrow_forwardThe probability of passing the bar exam in a certain state is 2/3. If 10 people passed the test at a college in that state, then find the most likely value for the number of people who failed the test at that college.arrow_forward
- Frank noticed that his mother will serve salad with dinner 78% of the nights, will serve potatoes with dinner 30% of the nights and will serve both 14% of the nights. The probability, to the nearest hundredth, that Frank's mother will serve salad or potatoes isarrow_forwardUse the following table for the next two questions. The following data represent the number of male and female students enrolled in nursing at the University of Oklahoma Health Sciences Center for a recent semester. A student is selected at random. Find the probability of each event. Nursing majors 180 1010 1190 Males Females Totals 23. The student is a male or nursing majors? (a) 1.0222 (b) 0.6200 (c) 0.6101 (d) 0.5750 Non-nursing majors 1110 1700 2810 Totals 1290 2710 4000 (e) 0.0450 24. Given that the selected student is female, find the probability that the student is a nursing major? (e) 0.1200 (a) 0.0380 (b) 0.2525 (c) 0.3727 (d) 0.9772arrow_forwardA factory produces a particular electrical component. On average, the probability that a component will be faulty is 0.16, independently of each other. The company sells the electrical component in a box of 7. Calculate the probability of having at least 1 faulty components. (2 d.p.)arrow_forward
- A First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON
