d) Fe2+/Fe + Zn2+/Zn chemPad XoXº E° = .31 Greek Zn (s) + Fe²+ (aq) Zn²+ (aq) + Fe ( Zn (s) + Fe^2+ (aq) --> Zn^2+ (aq) + Fe (s) Correct. X V Help n (moles of e) = 2

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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Use the Standard Reduction Table to answer the following questions.
Write a balanced net redox equation and determine both the standard cell potential and the number of electrons transferred for the spontaneous redox process that occurs when the following couples are connected. Use the lowest possib
matter under the given conditions in your answer. For the reaction arrow, please use an extensive arrow to the right (-->).
d) Fe2+/Fe + Zn²+/Zn
chemPad
XX→←
Zn (s) + Fe2+ (aq) → Zn²+ (aq) + Fe (
Zn (s) + Fe^2+ (aq) --> Zn^2+ (aq) + Fe (s)
Correct.
E° = .31
Reduction half-reactions
Li¹+ (aq) + e¹-
K¹+ (aq)+ e¹-
Ba²+ (aq) + 2 e¹-
Ca²+ (aq) + 2 e¹-
Na¹ + (aq) + e¹-
Mg²+ (aq) + 2 e¹-
Al³+ (aq) + 3 e¹-
U³+ (aq) + 3 e¹-
Ti²+ (aq) + 2 e¹-
Mn²+ (aq) + 2 e¹-
2 H₂O +2 e¹-
Zn²+ (aq) + 2 e¹-
Cr³+ (aq) + 3 e¹-
HCHO(aq) + 2 H₂O +2e¹-
Fe²+ (aq) + 2 e¹-
2 H₂O +2 e¹-
X V
Cd²+ (aq) + 2 e¹-
PbSO4(s) + 2 e¹-
In³+ (aq) + 3 e¹-
Co²+ (aq) + 2 e¹-
→ Help
Greek
n (moles of e") = 2
E°(V)
-3.04
-2.92
-2.92
-2.84
-2.71
-2.36
-1.66
-1.66
-1.63
-1.18
-0.83
-0.76
-0.74
CH3OH(aq) + 2 OH¹-(aq) -0.59
Fe(s)
H₂(g) + 2 OH¹ (aq)
Cd(s)
Pb(s) + SO4² (aq)
-0.44
-0.41*
-0.40
-0.36
In(s)
-0.34
-0.28
Co(s)
Li(s)
K(s)
Ba(s)
Ca(s)
Na(s)
Mg(s)
Al(s)
U(S)
Ti(s)
Mn(s)
H₂(g) + 2 OH¹ (aq)
Zn(s)
⇒ Cr(s)
Sn²+ (aq) + 2 e¹-
Pb²+ (aq) + 2 e¹-
2 H¹*(aq) +2e¹-
Sn4+ (aq) +2e¹-
Cu²+ (aq) + e¹-
CIO4¹ (aq) + H₂O() +2e¹-
AgCl(s) + e¹-
PbO₂(s) + 2 H¹*(aq) + 2 e¹-
Cu²+ (aq) + 2 e¹-
Ag2O(s) +H₂O +2e¹1-
CIO3¹ (aq) + H₂O() +2e¹-
O2(g) + 2 H₂O + 4e¹-
12(3)+2e¹-
CIO₂¹ (aq) + H₂O() +2e¹-
2 AgO(s) + H₂O +2e¹-
O₂(g) + 2 H¹+ (aq) + 2e¹-
Fe³+ (aq) + e¹-
Bro¹-(aq) + H₂O +2 e¹-
Ag¹+ (aq) +el-
O₂(g) + 4 H¹*(aq) + 4e¹-
H₂O₂(aq) +2e¹-
CIO¹ (aq) + H₂O +2e¹-
Hg2+ (aq) + 2 e¹-
NO3(aq) + 4 H¹+ (aq) + 3 e¹-
VO₂¹(aq) + 2 H¹*(aq) + e¹-
Bron+2e¹-
Sn(s)
Pb(s)
=H₂(g)
-0.14
-0.13
0.00
Sn²(aq)
+0.15
Cu¹*(aq)
+0.16
CIO3¹ (aq) + 2 OH¹ (aq) +0.17
+0.22
+0.28
Cu(s)
+0.34
2 Ag(s) + 2 OH¹-(aq)
+0.34
CIO₂¹(aq) + 2 OH¹ (aq) +0.35
+0.40
Ag(s) + C1¹ (aq)
PbO(s) + H₂O
4 OH¹ (aq)
21¹-(aq)
CIO¹ (aq) + 2 OH¹-(aq)
Ag₂O(s) + 2 OH¹ (aq)
= H2O2(80)
Fe²+ (aq)
Br¹-(aq) + 2 OH¹-(aq)
Ag(s)
⇒ 2 H₂O
⇒2 OH¹ (aq)
CI¹(aq) + 2 OH¹-(aq)
Hg()
NO(g) + 2 H₂O
VO² (aq) + H₂O
2 r¹(a)
+0.54
+0.59
+0.60
+0.70
+0.77
+0.77
+0.80
+0.82*
+0.88
+0.89
+0.85
+0.96
+1.00
+1.09
Ar
Transcribed Image Text:Use the Standard Reduction Table to answer the following questions. Write a balanced net redox equation and determine both the standard cell potential and the number of electrons transferred for the spontaneous redox process that occurs when the following couples are connected. Use the lowest possib matter under the given conditions in your answer. For the reaction arrow, please use an extensive arrow to the right (-->). d) Fe2+/Fe + Zn²+/Zn chemPad XX→← Zn (s) + Fe2+ (aq) → Zn²+ (aq) + Fe ( Zn (s) + Fe^2+ (aq) --> Zn^2+ (aq) + Fe (s) Correct. E° = .31 Reduction half-reactions Li¹+ (aq) + e¹- K¹+ (aq)+ e¹- Ba²+ (aq) + 2 e¹- Ca²+ (aq) + 2 e¹- Na¹ + (aq) + e¹- Mg²+ (aq) + 2 e¹- Al³+ (aq) + 3 e¹- U³+ (aq) + 3 e¹- Ti²+ (aq) + 2 e¹- Mn²+ (aq) + 2 e¹- 2 H₂O +2 e¹- Zn²+ (aq) + 2 e¹- Cr³+ (aq) + 3 e¹- HCHO(aq) + 2 H₂O +2e¹- Fe²+ (aq) + 2 e¹- 2 H₂O +2 e¹- X V Cd²+ (aq) + 2 e¹- PbSO4(s) + 2 e¹- In³+ (aq) + 3 e¹- Co²+ (aq) + 2 e¹- → Help Greek n (moles of e") = 2 E°(V) -3.04 -2.92 -2.92 -2.84 -2.71 -2.36 -1.66 -1.66 -1.63 -1.18 -0.83 -0.76 -0.74 CH3OH(aq) + 2 OH¹-(aq) -0.59 Fe(s) H₂(g) + 2 OH¹ (aq) Cd(s) Pb(s) + SO4² (aq) -0.44 -0.41* -0.40 -0.36 In(s) -0.34 -0.28 Co(s) Li(s) K(s) Ba(s) Ca(s) Na(s) Mg(s) Al(s) U(S) Ti(s) Mn(s) H₂(g) + 2 OH¹ (aq) Zn(s) ⇒ Cr(s) Sn²+ (aq) + 2 e¹- Pb²+ (aq) + 2 e¹- 2 H¹*(aq) +2e¹- Sn4+ (aq) +2e¹- Cu²+ (aq) + e¹- CIO4¹ (aq) + H₂O() +2e¹- AgCl(s) + e¹- PbO₂(s) + 2 H¹*(aq) + 2 e¹- Cu²+ (aq) + 2 e¹- Ag2O(s) +H₂O +2e¹1- CIO3¹ (aq) + H₂O() +2e¹- O2(g) + 2 H₂O + 4e¹- 12(3)+2e¹- CIO₂¹ (aq) + H₂O() +2e¹- 2 AgO(s) + H₂O +2e¹- O₂(g) + 2 H¹+ (aq) + 2e¹- Fe³+ (aq) + e¹- Bro¹-(aq) + H₂O +2 e¹- Ag¹+ (aq) +el- O₂(g) + 4 H¹*(aq) + 4e¹- H₂O₂(aq) +2e¹- CIO¹ (aq) + H₂O +2e¹- Hg2+ (aq) + 2 e¹- NO3(aq) + 4 H¹+ (aq) + 3 e¹- VO₂¹(aq) + 2 H¹*(aq) + e¹- Bron+2e¹- Sn(s) Pb(s) =H₂(g) -0.14 -0.13 0.00 Sn²(aq) +0.15 Cu¹*(aq) +0.16 CIO3¹ (aq) + 2 OH¹ (aq) +0.17 +0.22 +0.28 Cu(s) +0.34 2 Ag(s) + 2 OH¹-(aq) +0.34 CIO₂¹(aq) + 2 OH¹ (aq) +0.35 +0.40 Ag(s) + C1¹ (aq) PbO(s) + H₂O 4 OH¹ (aq) 21¹-(aq) CIO¹ (aq) + 2 OH¹-(aq) Ag₂O(s) + 2 OH¹ (aq) = H2O2(80) Fe²+ (aq) Br¹-(aq) + 2 OH¹-(aq) Ag(s) ⇒ 2 H₂O ⇒2 OH¹ (aq) CI¹(aq) + 2 OH¹-(aq) Hg() NO(g) + 2 H₂O VO² (aq) + H₂O 2 r¹(a) +0.54 +0.59 +0.60 +0.70 +0.77 +0.77 +0.80 +0.82* +0.88 +0.89 +0.85 +0.96 +1.00 +1.09 Ar
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