1. FizzBuzz 2.0by CodeChum AdminRemember the game of FizzBuzz from the lasttime? Well, I thought of some changes in thegame, and also with the help of loops as well.Firstly, you'll be asking for a random integerand then loop from 1 until that integer. Then,implement these conditions in the game:• print "Fizz" if the number is divisible by3• print "Buzz" if the number is divisible by5• print "FizzBuzz" if the number isdivisible by both 3 and 5• print the number itself if none of theabove conditions are metInput1. An integerOutputThe first line will contain a message prompt toinput the integer.The succeeding lines will contain either a stringor an integer.Enter n: 1512Fizz4BuzzFizz78FizzBuzzmain.c9101112=======2==*****13141516171819202122232425262728#includemainint n;printf("Enter n: ");scanf("%d,&n");int n1 = 0;}while (n-c-n1):{if (n%30 && n%5--0);{printf("fizzbuzz");}else if("%3--0");{printf("fizz");}else if("%5--0");{printf("buzz");}}Test CasesExecutionsmain.c:20:5: error: 'else' without a previous 14"20 | else if("nXS--0");IExpected OutputEnter n: 1512FIZZ4BuzzFizz78FizzBuzz11Fizz1314FizzBuzzⒸ Test Case 2Ⓒ Test Case 3

#include<stdio.h>void main(){int n;printf("Enter n: ");scanf("%d",&n);for(int…

Answered: ); D: ¡ D: ; ); Test Cases main.c:2015:…

); D: ¡ D: ; ); Test Cases main.c:2015: error: else without a previous "14" 201 else if("nXS-8"); Executions Expected Output Enter n: 15 1 2 Fizz 4 Buzz Fizz 7 Buzz 11 Fizz 13 14

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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