d D Aidona Grish Which of the following would be expected from breeding experiments involving these genes? Select all that apply. - Genes A and B show strong linkage, but genes C and D show little to no linkage. O More genetic recombinants would be observed for genes A and C than for genes A and D. Genes B and C show strong linkage, but genes A and B show little to no linkage. O More genetic recombinants would be observed for genes A and D than for genes B and C.
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- An organism described as 2n=4 has the chromosomes below with genes indicated by letters and centromeres indicated by periods. Select the BEST description of the chromosome aberration present in this organism. HJM.NPQ HJM.NPQ S.TVXZ S.TVXXVZ Select one: 0 a. Paracentric Inversion O b. Reverse Tandem Duplication Oc. Robertsonian Translocation Od. Terminal Deletion e. Tandem Duplication Of. Nonreciprocal Translocation g. Interstitial Deletion Oh. Pericentric Inversion Homobrachial Displaced Duplication Oj. Heterobrachial Displaced Duplication Ok. Reciprocal TranslocationAn organism described as 2n=4 has the chromosomes below with genes indicated by letters and centromeres indicated by periods. Select the BEST description of the chromosome aberration present in this organism. EGHI.LNP El.LNP QTWZ QTWVZ Select one. O a. Pericentric Inversion O b. Homobrachial Displaced Duplication O c. Interstitial Deletion O d. Robertsonian Translocation O e. Reverse Tandem Duplication Of Terminal Deletion O g. Heterobrachial Displaced Duplication O h. Tandenm Duplication O Nonreciprocal Translocation 01 Reciprocal Translocation Ok. Paracentric InversionTick all the essential steps to demonstrate a genetic linkage between a disease and a molecular marker in humans. identify the alleles of the genetic marker only for diseased individuals in the pedigree enumerate parental type individuals sequence the wild-type and mutant alleles to find the mutation no correct answer calculate a Lod score calculate the recombination frequency between the mutation and the molecular marker identify the alleles of the genetic marker for each individual in the pedigree pedigree analysis cloning the defective gene enumerate recombinant individuals
- Punnett Square for a Dihybrid Cross to Investigate Coat Colour in Mice be Вс BbCc Answer: D Ova BBCC BbCc bc) bb Cc (BC) BbCC D BbCc Bbcc X BBCC bbcc BBcc bbcc Bb Cc BC O Sperm BbCC Bb Cc Bbcc bc BBCC bbcc Вс BbCc Legend Black Brown White Coat colour in mice is controlled by the interaction of two genes. Three phenotypes result: black coat, brown coat, and white coat. The expected phenotypic ratio resulting from a cross between a bbCc female mouse and BbCc male mouse, is black: brown : white Enter only the number values in the order black brown white (Do not include spaces, commas, etc.)Construct a chromosome map from the following charts showing crossover frequencies for linkage groups on autosomes. (this one is tricky due to the unusual recombinations Gene Combinations Recombination Frequency y/w 2.2 v/m 3.0 v/r 26.6 v/w 30.0 v/y 32.2 w/m 33.0 y/m 35.2 w/r 56.6. A three-point testcross was made in corn. The results and a recombination analysis are shown in the display below, which is typical of three-point testcrosses (p = purple leaves, + = green; v = virus-resistant seedlings, + = sensitive; b = brown midriff to seed, + = plain). Study the display, and answer parts a through c.
- What would justify the following ratio appearing after phenotyping the outcome of a crossing trial: 8.9: 2.9: 3.2:1? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b C d Obviously this represents independent assortment based on crossing dihybrid heterozygotes. Obviously this represents gene linkage based on test crossing a dihybrid heterozygote. Obviously this represents the results of a trihybrid test cross. Obviously this represents independent assortment based on crossing monohybrid heterozygotes.A contig map for a chromosome in Drosophila is shown below. The chromosome has 10 segments, numbered 1- 10. Drosophila Chromosome 1 2 4 7 9 10 A Genomic Clones C D E If an EST hybridizes with genomic clones C, D and E, but not with the other clones, in which segment of the chromosome is the EST found? Enter a number. If a clone of gene GLO hybridizes only with genomic clones F and G, in which chromosome segment is gene GLO located? Enter a number. If a restriction fragment hybridizes with only one of the genomic clones, in which chromosome segment(s) could the fragment be found? Enter numbers for each segment ordered from smallest to largest separated by commas and no spaces. (Le. 4.8,10)In a haploid yeast strain, eight recessive mutationswere found that resulted in a requirement for theamino acid lysine. All the mutations were found to revert at a frequency of about 1 × 10−6 except mutations5 and 6, which did not revert. Matings were madebetween a and α cells carrying these mutations. Theability of the resultant diploid strains to grow onminimal medium in the absence of lysine is shown inthe following chart (+ means growth and − means nogrowth.)1 2 3 4 5 6 7 81 − + + + + − + −2 + − + + + + + +3 + + − − − − − +4 + + − − − − − +5 + + − − − − − +6 − + − − − − − −7 + + − − − − − +8 − + + + + − + −a. How many complementation groups were revealedby these data? Which point mutations are foundwithin which complementation groups?The same diploid strains are now induced to undergosporulation. The vast majority of resultant spores areauxotrophic; that is, they cannot form colonies whenplated on minimal medium (without lysine). However,particular diploids can produce rare spores…
- How would one explain a testcross involving F1 dihybrid flies in which more parental-type offspring than recombinant-type offspring are produced? Group of answer choices A. The testcross was improperly performed B. The two genes are linked C. Both of the characters are controlled by more than one gene D. The two genes are linked but on different chromosomes E. Recombination did not occur in the cell during meiosis. A true-breeding strain of Virginia tobacco has dominantalleles determining leaf morphology (M), leaf color(C), and leaf size (S). A Carolina strain is homozygousfor the recessive alleles of these three genes. Thesegenes are found on the same chromosome as follows:M C S6 m.u. 17 m.u.An F1 hybrid between the two strains is now backcrossedto the Carolina strain. Assuming no interference:a. What proportion of the backcross progeny willresemble the Virginia strain for all three traits?b. What proportion of the backcross progeny willresemble the Carolina strain for all three traits?c. What proportion of the backcross progeny will havethe leaf morphology and leaf size of the Virginiastrain but the leaf color of the Carolina strain?d. What proportion of the backcross progeny will havethe leaf morphology and leaf color of the Virginiastrain but the leaf size of the Carolina strain?An organism described as 2n=D4 has the chromosomes below with genes indicated by letters and centromeres indicated by periods. Select the BEST description of the chromosome aberration present in this organism. EFGKMN EF.GKMKMN RT.VXZ RT.VXZ Select one: O a. Robertsonian Translocation O b. Paracentric Inversion O c. Homobrachial Displaced Duplication O d. Reciprocal Translocation O e. Interstitial Deletion f. Reverse Tandem Duplication O g. Nonreciprocal Translocation O h. Heterobrachial Displaced Duplication Terminal Deletion Tandem Duplication O k. Pericentric Inversion