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(D? - 1)y = 2t -4 Ost<2 t22 v(0)-0, y'(0)-1 Find Lly) L (y) =D 1+ 를-- 2e-2s 2e-2s s2 L (1) = + - 4 2e-2s 2-1 62(32-1) 이(32-1) (62–1) s(s2–1) 2e-2 L (4) = -1) 4 2e-2, be 24 s(s2–1) s? (s²–1) ' (s2–1) L (14) = F 1) 2 4 2e-2 2e-2, s2 (s2 –1) s(s? -1) (s2 –1) s2 (s2 -1)

(D? - 1)y = 2t -4 Ost<2 t22 v(0)-0, y'(0)-1 Find Lly) L (y) =D 1+ 를-- 2e-2s 2e-2s s2 L (1) = + - 4 2e-2s 2-1 62(32-1) 이(32-1) (62–1) s(s2–1) 2e-2 L (4) = -1) 4 2e-2, be 24 s(s2–1) s? (s²–1) ' (s2–1) L (14) = F 1) 2 4 2e-2 2e-2, s2 (s2 –1) s(s? -1) (s2 –1) s2 (s2 -1)

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.5: Differentials: Linear Approximation
Problem 1YT: YOUR TURN Find dy if y=300x23,x=8, and dx=0.05.
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2t -4 Ost< 2 (D? - 1)y = t22 v(0)-0, y'(0)-1 Find Lly) L (v) =D 1+ 를-- 2e-2s s2 2e-2s L (4) = + - 2 4 2e-25 2e-24 s? (s² –1) (s2–1) 2-1 )1- 2و( 2ي s(s2–1) L (y) = t –1) 4 2e-2 be 2s s(s?-1) s? (s²–1) ' (s?–1) L (1) = F-1 -1) 2 4 2e-2s 2e-2s s2 (s2 –1) s(s2-1) s2 (s² –1) (s2 –1)
Transcribed Image Text:2t -4 Ost< 2 (D? - 1)y = t22 v(0)-0, y'(0)-1 Find Lly) L (v) =D 1+ 를-- 2e-2s s2 2e-2s L (4) = + - 2 4 2e-25 2e-24 s? (s² –1) (s2–1) 2-1 )1- 2و( 2ي s(s2–1) L (y) = t –1) 4 2e-2 be 2s s(s?-1) s? (s²–1) ' (s?–1) L (1) = F-1 -1) 2 4 2e-2s 2e-2s s2 (s2 –1) s(s2-1) s2 (s² –1) (s2 –1)
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