Cyber Monday Shopping A survey of 850 U.S. adults found that 32% of people said that they would get no work done on Cyber Monday since they would spend all day shopping online. Find the 99% confidence interval of the true proportion. Round intermediate answers to at least five decimal places. Round your final answers to at least three decimal places. ☐

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
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Cyber Monday Shopping A survey of 850 U.S. adults found that 32% of
people said that they would get no work done on Cyber Monday since they
would spend all day shopping online. Find the 99% confidence interval of the
true proportion. Round intermediate answers to at least five decimal places.
Round your final answers to at least three decimal places.
☐<p<0
Transcribed Image Text:Cyber Monday Shopping A survey of 850 U.S. adults found that 32% of people said that they would get no work done on Cyber Monday since they would spend all day shopping online. Find the 99% confidence interval of the true proportion. Round intermediate answers to at least five decimal places. Round your final answers to at least three decimal places. ☐<p<0
decimal places. Round your final answers to at
least three decimal places.
Explanation
Formula for a Specific Confidence Interval
for a Proportion
A
P-²a/2 · <p<p +²α/²\/
pa
pq
n
n
when n p and nq are each greater than or
equal to 5.
Since a 1-0.9=0.1, ²a/2 = 1.65.
Find p and q.
p = 0.32
q=1-p=1-0.32
= 0.68
Calculate the confidence interval.
7-2222-²2-124
pq
pa
P-²a/2
<p<p +²a/2
n
n
(0.32) (0.68)
(0.32) (0.68)
0.32 1.65
<p<0.32+ 1.65
900
900
0.32 0.02566<p<0.32+0.02566
0.294<p<0.346
Hence, we can be 90% confident that the
proportion of U.S. adults who would not get work
done on Cyber Monday is between 0.294 and 0.346,
based on a sample of 900 adults.
Transcribed Image Text:decimal places. Round your final answers to at least three decimal places. Explanation Formula for a Specific Confidence Interval for a Proportion A P-²a/2 · <p<p +²α/²\/ pa pq n n when n p and nq are each greater than or equal to 5. Since a 1-0.9=0.1, ²a/2 = 1.65. Find p and q. p = 0.32 q=1-p=1-0.32 = 0.68 Calculate the confidence interval. 7-2222-²2-124 pq pa P-²a/2 <p<p +²a/2 n n (0.32) (0.68) (0.32) (0.68) 0.32 1.65 <p<0.32+ 1.65 900 900 0.32 0.02566<p<0.32+0.02566 0.294<p<0.346 Hence, we can be 90% confident that the proportion of U.S. adults who would not get work done on Cyber Monday is between 0.294 and 0.346, based on a sample of 900 adults.
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