**Title:** Understanding Electron Flow in Chemical Reactions**Curved Arrows in Mechanistic Steps****Instruction:**Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic steps.Be sure to account for all bond-breaking and bond-making steps.**Reaction Details:**- **Reagents:** CH₃CH₂OK, CH₃CH₂OH- **Conditions:** Heat**Diagram Explanation:**The image shows a chemical diagram with a series of structural formulas:1. **Left Structure:** - An ethoxide ion (CH₃CH₂O⁻) with a lone pair of electrons on the oxygen atom.2. **Middle Structure:** - A secondary alkyl halide with a bromine atom attached, depicted using its structure: - Central carbon atoms bonded with Hydrogen (H), a Bromo group (Br), and other carbon chains. - Potassium ion (K⁺) is shown nearby.3. **Right Structure:** - An ethanol molecule (CH₃CH₂OH) with the oxygen atom connected to hydrogen.**Instructions for Drawing:**To complete the mechanistic steps, identify and draw the arrows indicating electron movement. These arrows should show:- How electrons shift from the nucleophile (ethoxide ion) to the electrophilic site (carbon attached to bromine) for potential substitution or elimination.- The movement of electrons in bond-breaking (e.g., breaking C-Br bond) and bond-forming (e.g., forming a new C-O bond) processes.Ensure that all steps reflect the proper electron flow in the reaction's transformation. The image depicts a chemical reaction involving the conversion of a bromide compound using a potassium ethoxide (CH₃CH₂OK) and ethanol (CH₃CH₂OH) solution under heat. Here is a detailed breakdown of the reaction:### Chemical Reaction:1. **Reaction Conditions and Reagents:** - **Reagents:** Potassium ethoxide (CH₃CH₂OK) and ethanol (CH₃CH₂OH) - **Conditions:** Heat is applied.2. **Reactants:** - A brominated compound with a structure shown on the right side: - It is a secondary alkyl bromide.3. **Products:** - An alkene structure formed by the elimination of HBr. - Side products may include the alcohol and/or leftover potassium.### Diagram Explanation:- **Left Side Diagram:** - **Ethoxide Ion (CH₃CH₂O⁻):** Shown as an ethyl group (two carbon chain) connected to an oxygen with a negative charge, and potassium as a counterion (K⁺). - **Starting Bromide Compound:** Displaying a secondary alkyl bromide, with the bromine atom carrying a partial negative charge (δ⁻).- **Right Side Diagram:** - **Formed Alkene:** The double bond is formed as a result of the elimination. - **Bromide Ion (Br⁻) and Ethanol:** As side products.The reaction is an example of an E2 elimination, where the ethoxide ion acts as a strong base, removing a hydrogen atom adjacent to the bromine-bearing carbon, leading to the formation of an alkene and the liberation of a bromide ion.

Organic reactant and products are given.We have to draw the arrow pushing mechanism for the given…

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic steps. Be sure to account for all bond-breaking and bond-making steps. Drawing Arrows CH3CH₂OK, CH3CH₂2OH heat H KO H H Undo Reset Done FO: H Drag To Pan

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic steps. Be sure to account for all bond-breaking and bond-making steps. Drawing Arrows CH3CH₂OK, CH3CH₂2OH heat H KO H H Undo Reset Done FO: H Drag To Pan

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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