College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- The force F has a magnitude of 480 Ib and acts along the diagonal of the parallelepiped as shown. Express Fin terms of its magnitude times the appropriate unit vector and determine its x-, y-, and z-components. A 6' F = 480 b 8' 3' B Answers: i+ i j+ i F= ( i Ib)( i Fx Ib i Fy Ib F2 Ib iarrow_forwardA force F1 of magnitude of 5 N is directed in 25 degrees East of South, and a force F2 of magnitude of 2 N is directed in 30 degrees North of West. 1. Draw each vector force and give the magnitude and the direction. 3. Component Method of Adding Vectors a. Find the x and y components of each vector. b. Determine the x and the y component of the resultant vector F3 = F1 + F2 . c. Calculate the magnitude and the direction of the resultant vector F3 .arrow_forwardTwo hockey players check an opponent into boards simultaneously. Player 1 hits from the left at an angle of 37 degrees to horizontal and a force of 400N. Player 2 hits from the left at an angle of 41 degrees to horizontal and a force of 600N. What is the magnitude and direction of total force applied to opposing playerarrow_forward
- 2. In mechanics, force is a vector quantity and has a unit of Newtons (N). The force F₁ with a magnitude of 54.0 N is applied at an object at the origin in the direction of 25° above the negative x-axis. A second force F₂ with a magnitude of 41.0 N is applied at the same object in the direction of 68° above the positive x-axis. Determine the magnitude and direction of the resultant of the two forces.arrow_forwardWrite the solution on a paper and round to 4 decimal placesarrow_forwardTwo ropes are attached to a tire on the ground. The first rope exerts a force of 205. N in a direction 14.9 degrees west of north. The second rope exerts a force of 362. N in a direction 27.6 degrees east of south. Find the magnitude (in N) of the net force on the tirearrow_forward
- The helicopter view in the figure below shows two people pulling on a stubborn mule. (Take F₁ = 137 N and F₂ = 74.0 N.) 75.0° direction 60.0⁰ x (a) Find the single force that is equivalent to the two forces shown. 149.56 magnitude Your response differs from the correct answer by more than 10%. Double check your calculations. N 23.65 X Your response differs from the correct answer by more than 10%. Double check your calculations. counterclockwise from the +x-axis (b) Find the force a third person would have to exert on the mule to make the net force equal to zero. magnitude N direction counterclockwise from the +x-axisarrow_forwardA force ofF1= 50.0 N is directed at an angle of 60° above the x-axis. A second force of F2 = 50.0 N is directed at an angle of 60.0° below the x-axis.= 50.0 N is directed at an angle of 60.0° below the x-axis. What is the vector sum of these two forces?arrow_forwardCalculating Net Force Two forces act on an object: 1) a force of magnitude F₁ and direction 0₁ 2) a force of magnitude F2 and direction 02 The net force on the object has a magnitude of Fnet and a direction of Onet. Solution: Forces must be added in component form (x and y separately): Fnet,x=F₁ cos 0₁ + F₂ cos 0₂ = Fnet CoS Onet Fnet.y Fnet sin net The 2 equations above have 6 variables. So if 4 variables are given, the equations can be solved. Tip: Plug in decimals for sines/cosines of known angles. = · F₁ sin 0₁ + F2 sin 0₂ = 3 4 F₁ 184N 305.6 F₁ N Type your answer... 0₁ 170⁰ 0₁ 156⁰ F₂ 349N F₂ 336N 02 289⁰ 02 301⁰ Fnet N Onet 244⁰ --DOarrow_forward
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