C(s) 10 = (s²+4s + 8) C(s) = 10 R(s) R(s) s²+4s+8' Let x₁ = c, x2 = Ċ; = X2, Then, 4c + 8c =10r Output y = c = x₁; B = dx1 dt [00] C = [10], and D = 0 dx2 dt = -4x2-8x1 + 10u matrices are A = = [ 08 [ 08 14 ] .

I have the following transfer function:

C(s)/R(s) = 10/(s^2 +4*s+8)

The picture below shows the matrix for the state-space representation of the given transfer function.I want to obtain the same result in MATLAB, but the B and C matrices are not matching the results from the picture, and I'm not sure why.

 My code is the following:

num=24;                            
den=[1 9 26 24];                    
[A,B,C,D]=tf2ss(num,den)            
                                    
'Phase-variable form'               
P=[0 0 1;0 1 0;1 0 0]; 
Ap=inv(P)*A*P                       
Bp=inv(P)*B                        
Cp=C*P                              
Dp=D