
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Create a Turing machine that computes a mapping reduction from L1 ≤ m L2 where L1 = {w : w ∈ {a,b}* and |W| is even} and where L2 = {anbn : n ≥ 0}
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- A finite automaton (FA) is an abstract machine that can be used to represent certain forms of computation in a graph that consists of states and edges from an alphabet Σ. Convert the following regular expression to finite automaton (FA): (a|b)*(abb|a)arrow_forwardLet L = { M| M is a Turing machine and L(M) is set of all binary 0,1-strings of even length}, where L(M) is the language accepted by Turing machine M. Prove that L is undecidable by finding a reduction from to it, where ={<M,w>| M is a Turing machine and M accepts w}.arrow_forwardExercise 2.29 Describe an algorithm that, given finite automata accepting lan- guages L1 and L2, determines if L1L2 = 0. %3Darrow_forward
- Construct a finite state automaton which recognizes strings over {a, b} which begin withbaab or ends with babb.arrow_forwardNFA 0’s near end or 1 at end: Write a nondeterministic finite automaton with at most 10 states that decides whether its input is contained in the following set: {x ∈ {0, 1}∗ | x[|x| − 5] = x[|x| − 2] = 0 or x[|x|] = 1}. We index strings starting at 1, so x[1] is the first symbol, and x[|x|] is the last symbol.arrow_forwardDraw out a determinism Turing machine that computes a mapping reduction from L1 ≤ m L2 where L1 = {w:w ∈ {a,b}* and |W| is even} and where L2 = {anbn:n ≥ 0}.arrow_forward
- For a Turing machine M, (M) refers to the binary representation of M. For a Turing machine M, L(M) contains the set of all strings accepted by M. For a Turing machine M and an input x = {0,1}*, Steps(M, x) refers to the number of steps taken by M to execute on x before it halts. Here, one step of execution of M on x = one movement (left or right) of the tape head. For a Turing machine M and an input x = {0,1}*, we define the following: ReachCells(M,x) = {i : M reaches ith tape cell when M is executed on x} Informally, it contains all locations on the tape that are visited when M is ecuted on x. The leftmost location on the tape is the first tape cell, the location next to it is the second tape cell, and so on. A string w₁ is an anagram of w2 if w₁ can be obtained by rearranging the alphabets of w2. Formally, if w₁ is an n length string, wê is called an anagram of w₁ if there exists a permutation à on n elements such that π(w₁) = W2.arrow_forwardThe reverse function maps a string w to wR. Draw a multi-tape Turing machine that computes the reverse of a binary string. That is, given a binary string w as input, your Turing machine should compute wR, write the result to tape 1, and halt.arrow_forwarddraw a Turing Machine that accepts strings in each of the languages below. Includethe septuple of the language with transition functions as well. a . L = { a n bn an bn : n ≥ 1 } b . L = { a n b m an+m: n ≥ 0, m ≥ 1} c . L = {w : w ∈ { a ,b}+ , |w| is a multiple of 4} d. L = {a n bm bn am : m ≥ 1 , n > m } e. L = {wcw : w ∈ { a ,b}* }arrow_forward
- Consider the language L = {w010w | w ∈ Ld} Is this language recursively enumerable? Justify your answerarrow_forwardLetΣ ={a, b}. LetL={aibai|i≥0}.Give a Turing machine (TM) that accepts the languageL.Assume (as in the examples done in our course videos) that, when theTM starts, the head is on a blank symbol,∆, and the input string isimmediately after that blank symbol on the tape. For example, if theinput string wereaaabaaa, then the inital tape configuration would be∆aaabaaaarrow_forward
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