Create a PriorityVector equals method. If every pair of deleted related items would be equal, it returns true. How complicated is the equals method? (Hint: Removing values might not be necessary.)
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Create a PriorityVector equals method. If every pair of deleted related items would be equal, it returns true. How complicated is the equals method? (Hint: Removing values might not be necessary.)
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- The code given below represents a saveTransaction() method which is used to save data to a database from the Java program. Given the classes in the image as well as an image of the screen which will call the function, modify the given code so that it loops through the items again, this time as it loops through you are to insert the data into the salesdetails table, note that the SalesNumber from the AUTO-INCREMENT field from above is to be inserted here with each record being placed into the salesdetails table. Finally, as you loop through the items the product table must be update because as products are sold the onhand field in the products table must be updated. When multiple tables are to be updated with related data, you should wrap it into a DMBS transaction. The schema for the database is also depicted. public class PosDAO { private Connection connection; public PosDAO(Connection connection) { this.connection = connection; } public void…Create a key-indexed counting method that only requires a certain amount of extra space. Give evidence to support your version's stability or an opposing example.Need help debugging this method: remove(int id) removes the Student associated with this id; if the id is not found in the table or on the waitlist, then it should return null; otherwise, it should return the Student associated with the id. If the student that is removed was registered, then this student should be replaced by the student who is first in the waitlist queue. If the student who is removed was on the waitlist, then they should just be removed from the waitlist. public class Course { public String code; public int capacity; public SLinkedList<Student>[] studentTable; public int size; public SLinkedList<Student> waitlist; public Course(String code) { this.code = code; this.studentTable = new SLinkedList[10]; this.size = 0; this.waitlist = new SLinkedList<Student>(); this.capacity = 10; } public Course(String code, int capacity) { this.code = code;…
- Add in loader spinners within each button in the Logs page. Currently it takes a very long time to load players/stats/etc. This is understandable given the amount of data. While the query is going on behind the scenes, please add loaders into the buttons — Player, Stats, Min/Max Timestamps (and make them non-clickable) — so that is it clear what the user is waiting on. Here is the filter code: import { map } from 'lodash'import React from 'react'import { Button } from 'reactstrap' import * as Dropdowns from './dropdowns' const isSubmittable = filterOptions => {if (!filterOptions.sport|| !filterOptions.schema|| !filterOptions.event) return false return true} const BetFeedFilters = props => {const { metadata, selectedMetadata, updateApiDropdown, filterOptions, events, players, stats, timestamps, submitApiCall, loading } = props if (!metadata) return <div></div> return (<div style={{ paddingTop: 10, paddingBottom: 10, display: 'flex', flexDirection: 'column', gap: 20,…You are provided a list of projects and a list of dependencies (a list of pairings of projects in which the second project is reliant on the first). Before a project can be constructed, all of its dependencies must be built. Find a construction order that will allow the projects to be completed. Return an error if there is no proper construction order.EXAMPLEInput:projects: a, b, c, d, e, fdependencies: (a, d), (f, b), (b, d), (f, a), (d, c)Output: f, e, a, b, d, cRetrieving a value using its associated key can be accomplished using anindexer, which works just like an indexer for an array. A key is passed in asthe index value, and the value associated with the key is returned, unless thekey doesn’t exist, in which a null is returned.Write short code segment demonstrates how this technique works:
- You are given a list of projects and a list of dependencies (which is a list of pairs ofprojects, where the second project is dependent on the first project). All of a project's dependencies must be built before the project is. Find a build order that will allow the projects to be built. If there is no valid build order, return an error.EXAMPLEInput:projects: a, b, c, d, e, fdependencies: (a, d), (f, b), (b, d), (f, a), (d, c)Output: f, e, a, b, d, cYou are provided a list of projects and a list of dependencies (a list of pairings of projects in which the second project is reliant on the first). Before a project can be constructed, all of its dependencies must be built. Find a construction order that will allow the projects to be completed. Return an error if there is no valid build order. EXAMPLEInput:projects: a, b, c, d, e, fdependencies: (a, d), (f, b), (b, d), (f, a), (d, c)Output: f, e, a, b, d, cYou are to implement removeHead, and removeTail and you also have to create the following functions (for visual purposes of the detail explanation, header and trailer sentinels are described as h and t respectively): IMPORTANT NOTE: For all the methods that has the pos parameter i.e. addAt, removeAt, move, make sure to access that specified position from whichever is nearer - the head or the tail - similar to what we have done in the get method. Example DoublyLinkedList: h <-> 10 <-> 30 <-> 40 <-> 50 <-> t int add(int num) This will add the element num into the last element of the linked list and return the position of the newly-added element. In the above example, having add(60) will return 5 as it is the fifth position in the list. int remove(int num) This will remove the first instance of the element and return the position of the removed element. In the above example, having remove(40) will return 3 as 40 was the third element in the linked list…
- You are provided a list of projects as well as a list of dependencies (a list of pairs of projects where the second project is reliant on the first). Before a project can be constructed, all of its dependencies must be built. Find a construction order that will allow the projects to be completed. Return an error if there is no proper construction order. EXAMPLEInput:projects: a, b, c, d, e, fdependencies: (a, d), (f, b), (b, d), (f, a), (d, c)Output: f, e, a, b, d, cWrite a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes…What is the difference between the remove and discard methods?