Create a function that would accept and integer as and display its binary sequence starting from zero to num. use this function definition: function treebinary(num) { example code and output: treeBinary(6) • 0000 • 0001 • 0010 • 0011 • 0110 • 0101 • 0110
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Implement the following JavaScript function
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- Code in C++ only In a rooted tree, the lowest common ancestor (or LCA for short) of two vertices u and v is defined as the lowest vertex that is ancestor of both that two vertices. Given a tree of N vertices, you need to answer the question of the form "r u v" which means if the root of the tree is at r then what is LCA of u and v. Input: 12 23 14 2 142 242 Output: 1Write the following function: The function gets a root of a Binary Tree of ints, and a function f. it applies f to the data of each node in the tree. // applies f to each node of the tree under root void map(BTnode_t* root, int (*f)(int)); struct BTnode { int value; struct BTnode*left; struct BTnode*right; struct BTnode*parent; }; typedef struct BTnode BTnode_t; BTNODE.C: BTnode_t* create_node(int val) { BTnode_t* newNode = (BTnode_t*) malloc(sizeof(BTnode_t)); newNode->value = val; newNode->left = NULL; newNode->right = NULL; newNode->parent = NULL; returnnewNode; } void set_left_child(BTnode_t* parent, BTnode_t* left_child) { if (parent) parent->left = left_child; if (left_child) left_child->parent = parent; } void set_right_child(BTnode_t* parent, BTnode_t* right_child) { if (parent) parent->right = right_child; if (right_child) right_child->parent = parent; } void print_pre_order(BTnode_t* root) { if (root == NULL) return; printf("%d ",…please I need a c++ implementation for this recursive function! Thank you in advance #ifndef H_binarySearchTree #define H_binarySearchTree #include <iostream> #include <cassert> #include "binaryTree.h" //************************************************************* // Author: D.S. Malik // // This class specifies the basic operations to implement a // binary search tree. // Revised by Dr. Ji on Npv 30 2021 //************************************************************* using namespace std; template<class elemType> class bSearchTreeType: public binaryTreeType<elemType> { public: bool search(const elemType& searchItem) const; //Function to determine if searchItem is in the binary //search tree. //Postcondition: Returns true if searchItem is found in the // binary search tree; otherwise, returns false. void insert(const elemType& insertItem); //Function to insert insertItem in the binary search tree. //Postcondition: If no node in the binary search tree has…
- C++ PROGRAM USE THE DRIVER CODE ATTACHED BELOW // { Driver Code Starts #include<bits/stdc++.h> using namespace std; // }Driver Code Ends class Solution { public: // Function to return a path vector consisting of vertex ids from vertex 0 to target vector shortestPath(int V, vector adj[], int target) { // Enter your code here! } }; // { Driver Code Starts int main() { int tc; cin >> tc; while (tc--) { int V, E, target; cin >> V >> E >> target; vector adj[V]; for (int i = 0; i < E; i++) { int u, v; cin >> u >> v; adj[u].push_back(v); // adj[v].push_back(u); } // string s1; // cin>>s1; Solution obj; vector ans = obj. shortestPath(V, adj, target); for (int i = 0; i < ans.size(); i++) { cout << ans[i] << " "; } cout << endl; } return 0; } // } Driver Code EndsA BST is constructed in the usual way using the node definition below. Write a function int child2( bst node t *curr) that returns the number of nodes that have 2 children. typedef struct BST NODE T {int data;struct BST NODE T *left, *right; } bst node t; int child2( bst node t *curr){ }Write a program in c++ which should create a weighted graph of the values entered by the user andthen write functions that perform the following: 1. Depth first search of source and destination vertex2. Breadth first search of source and destination vertex3. Shortest path search of source and all destination vertices (Dijkstra’s algorithm)4. Shortest path search of source and destination vertex (Dijkstra’s algorithm) The program should present a menu of the options and should run until the user opts to quit.
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