counter ← 0 total ← 0 2. while (counter <= 10) begin total ← total + 2 counter ← counter + 1 end
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In the next sequence, say whether the loop is finite or infinite. If the loop is finite, give the final value of the variable "total"; otherwise, if the loop is infinite, explain in detail why
1. counter ← 0
total ← 0
2. while (counter <= 10)
begin
total ← total + 2
counter ← counter + 1
end
Answer :
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- In the next sequence, say whether the loop is finite or infinite. If the loop is finite, give the final value of the variable "total"; otherwise, if the loop is infinite, explain why. total ←0 until (counter > 10) begin total ← total + 1 counter← counter + 1 end Memory counter Integer ? total Integer ? counter > 10 Boolean ? loop Finite Infinite total value totalthe total number of iterations of nested loops can be calculated by : O a. outer loop iterations / inner loop iterations O b. outer loop iterations + inner loop iterations O c. outer loop iterations - inner loop iterations O d. outer loop iterations * inner loop iterationsExamine the following while loops and determine the value of ires at the end of each of the loops, and the number of times each loop executes. (a) ires = 1; while mod (ires, 22) ires = ires + 1; end ires = number of times (b) ires = 2; while ires 100 ires = ires 2; end ires = number of times
- In the next sequence, say whether the loop is finite or infinite. If the loop is finite, give the final value of the variable "total"; otherwise, if the loop is infinite, explain why. counter←0 total ←0 while (counter <= 10) begin total ←total + 2 counter← counter + 1 end Memory counter Integer ? total Integer ? counter <= 10 Boolean Answer : Loop Finite Infinite total value totalot sum = 0 final int MAX ROWS 7, MAX COLS=5, int rows, columns for (rows 0, rowsExamine the following while loops and determine the value of ires at the end of each of the loops, and the number of times each loop executes. (a) ires = 1; while mod (ires, 15) = 0 ires = ires + 1; end ires = 15 number of times 16 (b) ires = 5; while ires 100 ires = ires^2; end ires = number of timesExamine the following for loops and determine the value of ires at the end of each of the loops, and also the number of times each loop executes. (a) ires = 0; for index - -18:18 ires = ires + 1; end ires = number of times (b) ires = 0; for index = 10:-2:1 if index == 6 continue; end ires = ires + index; end ires = number of times (c) ires = 0; for index = 10:-2:1 if index == 6 break; end ires = ires + index; end ires = number of times Activate WindowsWhat is the value of firstNum after the loop is terminated? int counter 0, firstNum 5; %3D while (counter < 10) { counter++; firstNum++; } firstNum =Examine the following for loops and determine the value of ires at the end of each of the loops, and also the number of times each loop executes. (a) ires = 0; for index -18:18 ires = ires + 1; end ires = number of times (b) ires = 0; for index = 10:-2:1 if index 6. == continue; end ires = ires + index; end ires = number of times (c) ires 0; for index = 10:-2:1 if index == break; end ires = ires + index; end ires = number of timesExamine the following for loops and determine the value of ires at the end of each of the loops, and also the number of times each loop executes. (a) ires = 0; for index = -11:11 ires = ires + 1; end ires = number of times (b) ires = 0; for index = 10:-2:1 if index == 6 continue; end ires = ires + index; end ires = number of times ires = 0; for index = 10:-2:1 if index == 6 (c) break; end ires = ires + index: end ires = number of times (d) ires = 0; for indexl = 10:-2:1 for index2 = 2:2:index1 if index2 == 6 break end ires = ires + index2; end end ires = number of times (outer loop) number of times (inner loop)Estimate how many times each loop will perform. Write a trace table for the following code (For instance, state the input and output value for each iteration of the loop).Step 1 In this step, we begin by filling in the following table with the values of a, b and the remainder of a mod b. a Step 3 Enter your final answer below: ged(a, b) = = b a mod b Step 2 Since the remainder we obtained in step 1 is not 0. We need to continue with the loop. Fill in the rest of the table. The process ends when the remair becomes 0. a b 105 341 a mod b 3SEE MORE QUESTIONS