Could you explain how the electrons flow in a saturated bjt using diagrams (and some words of course to explain it)? I understand that in forward active, the Ib is directly proportional to Ic. However, in saturation, I don't know how Ic is not dependent on Ib anymore. Im confused what will happen to the electrons coming from the emitter now that the collector-emitter junction is now forward-biased. It will also be helpful if you include the currents in the diagram. Thank you.

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BJT (Bipolar Junction Transistor)

A BJT is a semiconductor device with 3 terminals that consist of a p-n junction diode that can amplify the signal or current. It is a current-controlled device. The three BJT terminals are base, collector, and emitter. The BJT works with the charge carrier, the two type of carriers in the BJT are holes and electrons, the charge carriers flow by the process of recombination. The signal to be amplifier is generally given as the input at the base terminal and an amplified form of it is available at the collector terminal.