cos² 3ß – sin² 3ß

Q: 2. y = -2 cos -; 2 3. y =tan 2x

A: 2)  y=-2cos-x23)  y=12tan2x

Q: - cos2X -tan2X =tanx CosS 2X %3D

A:

Q: cos4A-sin4A=1-2sin2A

A: Solve the following

Q: cos(sec-'/1+x²)= Select one: 2x a. V1+x² O b. V1+x? 1 Oc. 1+x2 d. V1+x?

A:

Q: tan²(z) cos³(z)dæ

A:

Q: cos(2tan^-1 3/2)

A: Answer is in next step

Q: - cos 22.5°

A: Given: a) cos 22.5° b) tan9π8 To find: The exact value.

Q: 2. r=2-2 cos 0

A: Symmetry problem.....

Q: cos-1(2)

A:

Q: Solve 2 cos2 x + cos x - 1 = 0, 0 ≤ x < 2π

A: To solve: 2cos2x+cosx-1=0,0≤x≤2π. Solution: Given equation is: 2cos2x+cosx-1=0 On simplifying…

Q: 5. y=2 sin 20; 0=0,0=

A:

Q: cos 2x-1 i) x sin 2x 2 tan 30–20 ii) tan 40

A: follow next step.

Q: cos(B) = −³, π< ß < 2π.

A:

Q: 2 cos^2 θ-1=0

A:

Q: cos 4z - cos 2z =

A: cosx−cosy​=−2sinx+y2sinx−y​2​

Q: csc(x)=6 then sin(x/2) =

A: According to trigonometric properties; csc(x)=1sin(x) where x is in degrees or radians. It is given…

Q: */2 Cos Jo

A:

Q: 3 Simplify cos(arctan2). √5/5 no solution 2√5/5

A:

Q: 2ct-3) cos Cも-3) yct) = sin 2t cos 3t

A:

Q: COS 7t 6

A:

Q: Solve: 2 cos2 x + 3 sin x - 3 = 0, 0≤x &lt;2π.

A: We have to solve the equation 2cos2x+3sinx-3=0, 0≤x≤2π.

Q: ((/sin3z – cos2zV sin3z + cos2z bz

A: The objective is to solve the integration ∫sin3z-cos2zsin3z+cos2zdz Now,…

Q: マ-2SmA 2 Sin

A:

Q: b. Z1= 4(cos 200° + i sin 200°), z2= 25(cos 150° + i sin 150°)

A:

Q: ブーーコニメCos(2x 2.

A:

Q: cos 2π/ 3 ..........

A: Given expression: cos2π3

Q: cos (x) 2 %3D X = Submit

A:

Q: Cos2 π/3 + sin2 π/3

A:

Q: Solve y' = cos(2x + y – 5) – 2. = COS

A: The solution is given as

Q: (3-2)* V | (2r2 – 1) cos 3rdr | Cos

A:

Q: (b) . 2r sin- (2²) dr

A: We will use the method of substitution to solve the integral.

Q: I/2 52) 5), 5/2 6] Sin23xdx Cos'xdx

A: As we know that; The trigonometric identities; 1). sin2x=1-cos2x22). cos2x=2cos2x-1   5). Given:…

Q: sin5 4 3 cos6 4 4. dw

A: Giventhat:-∫π3π sin5 34ω cos6 34ω dωTo find:- value of IntegralSolution:- Integral ∫sin534ωcos6 34ω…

Q: Solve: cos 2x + 3sin x - 2 = 0, 0 ≤ x &lt; 2π.

A: We know that,  cos2x=1-2sin2x We have, cos2x+3sinx-2=0

Q: 3) cos -40 + 4) 1=-1 + 2tan -46

A: 1.

Q: Solve cos(2x) + cos(x) = -1

A:

Q: Solve y'-y cosx = cos x

A: We now solve the differential equation, y' -ycosx=cosx . This is a first order homogeneous equation.

Q: cos( + B) = O V2(cosB + V3sinB) V3(cosB - V2sinB) O V2(cosB - V3sinB)

A: Value of Cos(π/3 + B) will be

Q: 3) y(³) − y(¹) = cos(2x). —

A:

Q: Cos (tan (-1)) nin (con (-4))

A:

Q: | sin2xdx = %3D cos2x A O +C cos2x B O +C 2 cos2x+CCO -2 cos2x+CDO

A: ∫sin(2x)dx= -(cos2x)/2+C

Q: s cos 3ede CoS |- sinb

A: follow next step

Q: cos 0 = √√2 -|~

A: Let's find angle theta.

Q: Cos 0 do |3| 3 6. 0.

A: ∫06πcosθdθ    = sinθ06π    = sin6π-sin0    = 0 - 0   = 0

Q: Cos NT 33. У Зп + 2

A:

Q: 3e sin(6t) -3et cos(6t) SO: 3et cos(6t) 3et sin(6t)

A:

Q: ii) у" +у' — 6у%3 sin2x.

A:

Q: у%3D 3 cos x + x2

A:

Q: | sin(2x) 2) +c 2 + cos(2x) da 2

A:

Q: b.2 cos2 3x + sin3x = 1 %3D

A: