correction to this exercice and explain in sentence or two why I made the mis
correction to this exercice and explain in sentence or two why I made the mis
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Make correction to this exercice and explain in sentence or two why I made the mistake.
![hot required
1
1. (3) For the beam shown, in the space provided,
x
a.
500 kN-m
b.
250 N
30°
7.5 m
(2) Draw the Free Body Diagram for the beam
(1) Resolve the distributed load into 2 point loads, and indicate their location as a
0.2.
27m
distance from point O.
missing
reactions
6 kN/m
FRA
6KN/m
FR₂ =
IS KN
FR = EF = FRA + FR₂ + FR3
FR=521 KN/m/
ENGR&214
Fall 2023
0.4 m
4.5 m
30%
15 kN
B
ne tr
A
6 KN M
Öy
FR3
Initials
5m.
0819
0.15 m
+
FR = 521 KN
-442.5 KN
142.5KN/
2. (2) Draw the Free Body Diagram for the bar shown, in the space provided.
uppeR = = (6) (7.5)
FRA
→→16
(ES MRO = -FR₁ (5m) - FR₂ (7.5m) = -6 KN/m (5m) 15KN/m (7.5m)
+
(+5 MR₁ = -)
FR.d = HR d =
500 kN/m
IS KNM
2.5m 1.5m
FR2=(6X45
او الـ الـ
← A
HR
FR
Ау
500 KN/m
a moment!
142.5 KN
500 KNH
d=<0.27 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e7ba281-dd87-4688-be97-9abf26130e05%2Fbab69a6c-6f4a-4a7d-b0a6-456ba04b6231%2Fxvd7uda_processed.jpeg&w=3840&q=75)
Transcribed Image Text:hot required
1
1. (3) For the beam shown, in the space provided,
x
a.
500 kN-m
b.
250 N
30°
7.5 m
(2) Draw the Free Body Diagram for the beam
(1) Resolve the distributed load into 2 point loads, and indicate their location as a
0.2.
27m
distance from point O.
missing
reactions
6 kN/m
FRA
6KN/m
FR₂ =
IS KN
FR = EF = FRA + FR₂ + FR3
FR=521 KN/m/
ENGR&214
Fall 2023
0.4 m
4.5 m
30%
15 kN
B
ne tr
A
6 KN M
Öy
FR3
Initials
5m.
0819
0.15 m
+
FR = 521 KN
-442.5 KN
142.5KN/
2. (2) Draw the Free Body Diagram for the bar shown, in the space provided.
uppeR = = (6) (7.5)
FRA
→→16
(ES MRO = -FR₁ (5m) - FR₂ (7.5m) = -6 KN/m (5m) 15KN/m (7.5m)
+
(+5 MR₁ = -)
FR.d = HR d =
500 kN/m
IS KNM
2.5m 1.5m
FR2=(6X45
او الـ الـ
← A
HR
FR
Ау
500 KN/m
a moment!
142.5 KN
500 KNH
d=<0.27 m
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