correct answers only pls!Topic: BinaryFill in the boxesWill give you high rating thank you!! AddrAddr (Bin)Contents10 10 110 0 0 1O 000 0 0 o00 0 0 11 1 1 00 1 1 1 1 1 1 10 0 0 0 1 0 0 110 0 0 0 1 0 0 1 1 1 010 10 100 0 1 0 0 100 1 100 0 1 1 1 0 0 000 0000 000010 0100 0000 000111100 0000 00100 1 0 0 0 0 00 02300 0000 00111 0 0 01...1 1 0 0 1 10 0 1 0102111 1111 110110221 00 1111 1111 111011102311 1111 111111Address space from 0 to 2"-1 where n is the number of address bitsCan store 1024 words. Because each word is 2 bytes, can store 2048 bytes or 2kBThe address of the first word is 0, the second word is 1, the third word is 2, and the last word is 1023.Now, try to fill in the blanks for a word-addressable machine with 4 address lines, but the word size is 64 bits instead:• the memory size iswords, orbytes• the address of the first word is• the address of the second word is• the address of last word is1,

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Answered: correct answers only pls! Topic:…

Engineering

Computer Science

correct answers only pls! Topic: Binary Fill in the boxes Will give you high rating thank you!!

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

correct answers only pls!

Topic: Binary

Fill in the boxes

Will give you high rating thank you!!

Addr
Addr (Bin)
Contents
10 10 1
10 0 0 1
O 000 0 0 o00 0 0 1
1 1 1 0
0 1 1 1 1 1 1 10 0 0 0 1 0 0 1
10 0 0 0 1 0 0 1 1 1 0
10 10 10
0 0 1 0 0 10
0 1 100 0 1 1 1 0 0 0
00 0000 0000
1
0 0
1
00 0000 0001
1
1
1
00 0000 0010
0 1 0 0 0 0 0
0 0
2
3
00 0000 0011
1 0 0 0
1
...
1 1 0 0 1 10 0 1 0
1021
11 1111 1101
1022
1 00 1
1
11 1111 1110
1
1
1023
11 1111 1111
1
1
Address space from 0 to 2"-1 where n is the number of address bits
Can store 1024 words. Because each word is 2 bytes, can store 2048 bytes or 2kB
The address of the first word is 0, the second word is 1, the third word is 2, and the last word is 1023.
Now, try to fill in the blanks for a word-addressable machine with 4 address lines, but the word size is 64 bits instead:
• the memory size is
words, or
bytes
• the address of the first word is
• the address of the second word is
• the address of last word is
1,

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