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Ⓡ Copyright © The McGraw-Companies, Inc. Permission required for reproduction or display. (3, 0, 0) (1, 0, 0) Free space 2 MA - 15 A (1,2,0) A square loop of wire lies in the = 0 plane as above and carries a current of 2 mA in a counter-clockwise direction. An infinitely long filament of wire on the y-axis carries a current of 15 A in the -y direction. Find the total force on the loop of wire due to the infinite filament of current.

Ⓡ Copyright © The McGraw-Companies, Inc. Permission required for reproduction or display. (3, 0, 0) (1, 0, 0) Free space 2 MA - 15 A (1,2,0) A square loop of wire lies in the = 0 plane as above and carries a current of 2 mA in a counter-clockwise direction. An infinitely long filament of wire on the y-axis carries a current of 15 A in the -y direction. Find the total force on the loop of wire due to the infinite filament of current.

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completely separate from each other in this question (a) (b) (c) Copyright © The McGraw-H Companies, Inc. Permission required for reproduction or display. (3, 0, 0) 15 (1,0,0) 1. the electric field E; and 2. the volume charge density Note: parts (a), (b), and (c) are determine: Free space 2 mA A square loop of wire lies in the = 0 plane as above and carries a current of 2 mA in a counter-clockwise direction. An infinitely long filament of wire on the y-axis carries a current of 15 A in the y direction. Find the total force on the loop of wire due to the infinite filament of current. The scalar electric potential field in a region of free space is de- scribed by V = 2x²y-52. At the point P = (x = -4, y = 3, z = 6) determine and in region 2 at the interface is + 15 A (1,2,0) A unit normal vector from region 2 (u=2₁) to region 1 (= o) â:1 = If the magnetic field in region 1 at the material interface is H = 102 +ây +128, A/m 6a +2ây - 3a, H₂ = H₂ - 5ầy + 4â, A/m 1. Hand 2. the surface current density K at the interface
Transcribed Image Text:completely separate from each other in this question (a) (b) (c) Copyright © The McGraw-H Companies, Inc. Permission required for reproduction or display. (3, 0, 0) 15 (1,0,0) 1. the electric field E; and 2. the volume charge density Note: parts (a), (b), and (c) are determine: Free space 2 mA A square loop of wire lies in the = 0 plane as above and carries a current of 2 mA in a counter-clockwise direction. An infinitely long filament of wire on the y-axis carries a current of 15 A in the y direction. Find the total force on the loop of wire due to the infinite filament of current. The scalar electric potential field in a region of free space is de- scribed by V = 2x²y-52. At the point P = (x = -4, y = 3, z = 6) determine and in region 2 at the interface is + 15 A (1,2,0) A unit normal vector from region 2 (u=2₁) to region 1 (= o) â:1 = If the magnetic field in region 1 at the material interface is H = 102 +ây +128, A/m 6a +2ây - 3a, H₂ = H₂ - 5ầy + 4â, A/m 1. Hand 2. the surface current density K at the interface
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