Convert the condensed structures below into line-angle structures. Please note that some of the structures have “branches,” and some might have double or triple bonds. Please be very careful that you do not miss any hydrogen, carbon, nitrogen, oxygen, or sulfur. a.(N≡C)2CHCH2CH(CH=CH2)CH2C≡CCH2CH=O b. CH3OCH2S-SCCl2CH2CH=NCH2CO2H

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I have given you a condensed structure. You need to convert it to an accurate bond-line structure. CH3 CH3-CH-CH2-CH-CH₂-C-H 12-CH-CH2₂-C-1 CI Draw (as bond-line structures) isomers of this compound where you only move the chlorine atom. Draw four isomers of the original compound that would have a five carbon chain as the longest chain. [Note: there would be many isomers that will satisfy this. Find any four.] Using the original molecule (and looking at the carbon next to the aldehyde carbonyl) what would be the charge on that carbon if I removed an H atom and left behind the pair of electrons? Circle the best answer Positive Negative Neutral In the space below, draw that structure (from the sentence above) as a bond-line structure. Then, draw a resonance structure for this ion and be sure to add curved arrows to show the movement of electrons.

Which of these formulas is(are) not valid for octane?   A. C8H18B. C8H20C. C8H16D. CH3CH2CH2CH2CH2CH2CH2CH3E. CH3(CH2)6 CH3