Convert conductivity to molar concentration by using the initial conductivity of the NaOH solution as a conversion factor. Convert each initial rate into the units: mols/L/s. For example, if the initial conductivity of a 0.005 mol/L NaOH solution was 2000 uS/cm and initial rate was 5.0 uS/cm/s, you would convert the rate to moles/ L /s by completing the following calculations: Rate= 5.0uS/cm/s [(0.005 mol/L)(2000 uS/cm)]= 1.25 x 10^-5 mol/L/s.  After calculating using these new values out the rate constant for each trial, what is the average value of k?  Trial NaOH CH3COOC2H5 Initial Condcutivity of NaOH Solution (uS/cm) Initial Rate (uS/cm)/s) 1 21 ml 2.1ml 1285 24.72 2 21 ml 2.1ml 2399 50.32 3 21 ml 2.1ml 1262 23.72

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  1. Convert conductivity to molar concentration by using the initial conductivity of the NaOH solution as a conversion factor. Convert each initial rate into the units: mols/L/s. For example, if the initial conductivity of a 0.005 mol/L NaOH solution was 2000 uS/cm and initial rate was 5.0 uS/cm/s, you would convert the rate to moles/ L /s by completing the following calculations: Rate= 5.0uS/cm/s [(0.005 mol/L)(2000 uS/cm)]= 1.25 x 10^-5 mol/L/s. 
    After calculating using these new values out the rate constant for each trial, what is the average value of k? 

Trial

NaOH

CH3COOC2H5

Initial Condcutivity of NaOH Solution (uS/cm)

Initial Rate
(uS/cm)/s)

1

21 ml

2.1ml

1285

24.72

2

21 ml

2.1ml

2399

50.32

3

21 ml

2.1ml

1262

23.72

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