Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1
In the given question we have to convert the value of Fahrenheit into following units. i.e celcius (°C) and Kelvin (K)
we know that,
the given formula,
Converting from Fahrenheit to celcius
°C = (°F - 32 ) × (5/9)
Converting from Fahrenheit to Kelvin
K = (°F - 32 ) × (5/9) + 273.15
for 115.5 °F to celcius
by using the formula,
°C = (°F - 32 ) × (5/9)
= ( 115.5 - 32 ) × (5/9)
= 83.5 × (5/9) °C
= 417.5 / 9 °C
= 46.389 °C
for 115.5 °F to Kelvin
by using the above formula,
K = (°F - 32 ) × (5/9) + 273.15
= ( 115.5 - 32 ) × (5/9) + 273.15 K
= 83.5 × (5/9) + 273.15 K
= 46.389 + 273.15 K
= 319.54 K
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