MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Continuity Correction In testing the assumption that the
a. The probability of 502 or fewer boys
b. The probability of exactly 502 boys
c. The probability of more than 502 boys
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- K Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of μ = 1.3 kg and a standard deviation of a = 4.4 kg. Complete parts (a) through (c) below. a. If 1 male college student is randomly selected, find the probability that he gains between 0 kg and 3 kg during freshman year. The probability is (Round to four decimal places as needed.) b. If 25 male college students are randomly selected, find the probability that their mean weight gain during freshman year is between 0 kg and 3 kg. The probability is (Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? OA. Since the distribution is of individuals, not sample means, the distribution is a normal distribution for any sample size. OB. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size. OC.…arrow_forwardAssume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is between - 2.18 and 3.86 and draw a sketch of the region. Sketch the region. Choose the correct graph below. O A. В. OC. O D. -2.18 3.86 2.18 3.86 -2.18 3.86 -2.18 3.86 The probability is (Round to four decimal places as needed.) Click to select your answer(s). 山T00④ NOV 2. 1377 14 X P W MacBook Air esc 80 888 F3 F4 F7 FB F9 F10 $4 & 4 80 Q E Y A F G H. K /2x cv C V B D. 林 wwww wwwwwarrow_forwardAssume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P, the 11th percentile. This is the bone density score separating the bottom 11% from the top 89%. Which graph represents P ? Choose the correct graph below. O A. O B. OD. P11 P11 P11 P11 The bone density score corresponding to P1 is (Round to two decimal places as needed.) Click to select your answer(s). APR tv MacBook Air F9 F10 LLA 20 F3 F6 F8 F4 F5 F1 F2 & #3 7 8. %24arrow_forward
- Relax! A recent survey asked 1678 people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 112 1 185 2 337 3 254 4 318 5 230 6 150 7 30 8 62 Total 1678 Consider these 1678 people to be a population. Let X be the number of hours of relaxation for a person sampled at random from this population. (a) Compute the mean ux. Round the answer to two decimal places. (b) Compute the standard deviation ox. Round the answer to three decimal places.arrow_forward7tharrow_forwardThe round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 5.8 mm. Round values to 4 decimal places when possible. b. The standard deviation is c. The probability that the round a. The mean of this distribution is off error for a jumper's distance is exactly 0.3 is P(x-03)-d. The probability that the round off error for the distance that a long jumper has jumped is between 0 and 5 8 mm is PC1.7 x 5.2)- that the jump's round off error is greater than 1.76 is P(x > 1.76) Find the 81st percentile. e. The probability f P(x > 1.4 x > 0.6) h. Find the mnmum for the upper quartile.arrow_forward
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