Construct the Logic Gate Circuit for the following Boolean expressions (do not simplity)! Y = [A + (B+C)] × D a) 12 b) H the Y = (AxB)x (C ĐA) If
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![Construct the Logic Gate Circuit for the following Boolean expressions (do not simplity)!
Y = [A + (B+C)] × D
a)
12
b)
H the
Y = (AxB)x (C ĐA)
If](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F56fd0eef-63bd-46a8-93ef-18c62176ff10%2Fb5f0e6d6-7d11-499e-8fb1-468b118ba930%2F8623swa_processed.png&w=3840&q=75)
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- Draw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = FLogic Gates:* 7404LS (NOT)* 7408LS (AND)* 7432LS (OR)* 7400LS (NAND)* 7402LS (NOR)* 7486LS (EX-OR)Or you can use 74HCxx versions. Task 2: 4 INPUT PRIORITY ENCODERa) Write the truth table.b) Find the outputs in terms of min terms using minimal expression.c) By using K map, find the simple/simplest expression of theoutputs.d) Draw the circuit diagram. (Simulation design will be accepted.)e) Simulate the circuit & explain your results. (Please do notdesign separate simulations for each output. You should design ONEsimulation including all inputs and outputs.)Determine the truth table for the following logic circuit. Then identify the type of logic gate using Boolean algebra. O +Vcc R23 ER O O/P Q1 Q2 BO
- 1. a. i. Draw the gates required to build a half adder are ii. When simplified with Boolean Algebra (x + y)(x + z) simplifies to : iii. The output of a logic gate is 1 when all its inputs are at logic 0, the gate is either :T: Answer thne f. questions: 1) The hexadecimal number ´Al' has the decimal value equivalent to (A) 80 (B) 161 (C) 100 (D) 101 2) The output of a logic gate is 0 when all its inputs are logic 1. The logic is either (A) a NAND or an EX-OR (B) an OR or an EX-NOR (C) an AND or an EX-OR (D) an NOR or an EX-NOR 3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to (A) a (B) a+a(b+c) (C) a(1+bc) (D) a+bc 5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (B) 55 (C) 26 (D) 34 7) With 4 bit, what the range of decimal values if the number is 2's complement signed number. (A) -32 to +31 (B) -2 to +1 (C) -8 to +7 (D) None of theseIf a fault occurs in connections C5 (stuck-at-1) for the following logic circuit, the appropriate fault-test by using Boolean difference technique .......... C1 X1 Cs C2 X2 Cs C6 C10 C9 C7 t0 t2 t3 t1 O
- Problem #04] Using AND and OR gates develop the logic circuit for the Boolean equation shown below. Y =AB(C + DEF) + CE(A + B +F) Problem #05] Using AND and OR gates develop the logic circuit for the Boolean equation shown below. X-A(CD+B)2.1 Combinational logic circuits. Tabulates a truth table for the following Boolean expression shown in Equation 1.1. f = A.B.C + A.B.C + A.B.C (1.1) 2.2 Half adder. A half adder is a circuit that adds two binary digits, A and B. It has two outputs, sum (S) and carry (C). The carry signal represents an overflow into the next digit of a multi-digit addition. Figure 1.2 depicted a logic diagram for a half adder. a. derives the Boolean expression for s and c. b. tabulates a truth table for the half adder. Ao Bo Figure 1.2: Half adder os S CA combinational logic circuit that compares between two 2-bit numbers A (A1 A0) and B(B1 B0) is designed. Output F is high when ? > ? and low when ? < ?. 1) Are there any undefined outputs? If there are any undefined outputs what are the inputs?
- Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).Convert the following logic gate circuit into a Boolean expression, writing Boolean sub-expressions next to each gate output in the diagram: C DDAssuming we are given a Logic Gate network, the output of the circuit is given by the following equation Q=A.B+A.C+ A.B.C By using the Boolean Logic rules for simplification, select which of the following equations is the correct simplified one. Note that, the answer None of the above may sometimes be the correct response. Q=A+(B.C) O Q=A.(B.C) O Q=Ā. (B+C) ⒸQ=A. (B+C) None of the above O Not answered