Construct a 90% confidence interval of the population proportion using the given information. x = 80, n= 200 Click here to view the table of critical values. The lower bound is The upper bound is. (Round to three decimal places as needed.) - X Table of critical values Level of Confidence, Area in Each Tail,, Critical Value, z (1 - a)- 100% 90% 0.05 1.645 95% 0.025 1.96

Use technology to construct the confidence intervals for the population variance o? and the population standard deviation o. Assume the sample is taken from a normally distributed population. c= 0.99, s= 37, n 20 The confidence interval for the population variance is (Round to two decimal places as needed.) The confidence interval for the population standard deviation is (Round to two decimal places as needed.)

Suppose you take a random sample of n = 80 Douglas College students and ask each student their age. You find that the mean age of students in this sample is X = 22.0375 years and the sample standard deviation is s = 3.2014 years.  Fill in the blanks (rounding to four decimal places):  The 95% confidence interval for the mean age μ of all Douglas College students is from ______ years to ______ years.

Which two of the following could be confidence intervals with the same sample? (0.45, 0.75) (0.4, 0.5) (0.35, 0.45) (0.3, 0.6)