Constants An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface charge density 2.90x10 12 C/m? Part A How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 2.00x10 m from the sheet? Express your answer with the appropriate units. HA W = Value Units Submit Request Answer Part B What is the speed of the electron when it is 2.00x102 m from the sheet? Express your answer with the appropriate units. HA Value Units

Need help wtih parts A, B, and C pls

Part A An electron is moving east in a uniform electric field of 1.47 N/C directed to the west. At point A, the velocity of the electron is 4.46x105 m/s pointed toward the east. What is the speed of the electron when it reaches point B, which is a distance of 0.395 m east of point A? Express your answer in meters per second. V₁ = Submit Part B || ΑΣΦ ← Request Answer 给 ΑΣΦ A p=1.73.104 Ć A proton is moving in the uniform electric field of part A. At point A, the velocity of the proton is 1.92x10 m/s, again pointed towards the east. What is the speed of the proton at point B? Express your answer in meters per second. C 16 ? Submit Previous Answers Request Answer ? m/s * Incorrect; Try Again; 29 attempts remaining m/s

Learning Goal: To understand the relationship and differences between electric potential and electric potential energy. In this problem we will learn about the relationships between electric force F, electric field Ē, potential energy U, and electric potential V. To understand these concepts, we will first study a system with which you are already familiar: the uniform gravitational field. Part B Now find the gravitational potential energy U (z) of the object when it is at an arbitrary height z. Take zero potential to be at position z = 0. Keep in mind that the potential energy is a scalar, not a vector. Express U (2) in terms of m, z, and g. U (z) = Submit ΨΕ ΑΣΦ Request Answer ?