
Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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Question
![**Consolidation of Clay:**
**Objective:**
Given Exercise Figure 7.4 and accompanying information, determine the ultimate settlement in the clay under the applied load.
**Notes:**
- 1 ft = 0.3048 m
- 62.4 lb/ft³ = 1 Mg/m³
**Formula:**
Assuming the sand will not settle, the ultimate settlement in the clay can be calculated using the formula:
\[
\Delta H = \frac{H}{1 + e_0} C_c \log \left(1 + \frac{\Delta \sigma'}{\sigma'}\right)
\]
**Steps:**
a. **Effective Stress Determination:**
- Determine the effective stress for the cross section prior to loading. Use an appropriate diagram to show stresses at depth.
b. **Calculate \(\Delta \sigma'\):**
- Find the change in effective stress (\(\Delta \sigma'\)) on the clay layer caused by the imposed load. Calculate for the center of the clay layer at 5.8 m [19 ft] deep.
c. **Original Porosity (\(e_0\)):**
- Determine \(e_0\) based on the original porosity of the clay.
d. **Settlement Calculation:**
- Calculate how much settlement will occur in the clay.
**Exercise Figure 7.4: Explanation:**
The figure provides a cross-sectional view with the following layers:
- **0 to 5 ft:** Sand, dry unit weight \(\gamma_d = 105 \, \text{lb/ft}^3\)
- **5 to 16 ft:** Silty sand, saturated unit weight \(\gamma_{\text{sat}} = 127 \, \text{lb/ft}^3\), Groundwater Table (GWT) indicated at 5 ft
- **16 to 22 ft:** Clay, saturated unit weight \(\gamma_{\text{sat}} = 121 \, \text{lb/ft}^3\), with noted porosity (\(n = 0.629\)) and a compression index (\(C_c = 0.82\))
- **Load:** A point load of 125 tons is applied at the surface.
This setup is used to analyze the stress changes and resulting settlement in the clay layer.](https://content.bartleby.com/qna-images/question/8ea503b5-9839-4a05-b482-50f8a035eb54/21edf521-dffa-4368-807c-2b6ded900826/j9v9bhp_thumbnail.png)
Transcribed Image Text:**Consolidation of Clay:**
**Objective:**
Given Exercise Figure 7.4 and accompanying information, determine the ultimate settlement in the clay under the applied load.
**Notes:**
- 1 ft = 0.3048 m
- 62.4 lb/ft³ = 1 Mg/m³
**Formula:**
Assuming the sand will not settle, the ultimate settlement in the clay can be calculated using the formula:
\[
\Delta H = \frac{H}{1 + e_0} C_c \log \left(1 + \frac{\Delta \sigma'}{\sigma'}\right)
\]
**Steps:**
a. **Effective Stress Determination:**
- Determine the effective stress for the cross section prior to loading. Use an appropriate diagram to show stresses at depth.
b. **Calculate \(\Delta \sigma'\):**
- Find the change in effective stress (\(\Delta \sigma'\)) on the clay layer caused by the imposed load. Calculate for the center of the clay layer at 5.8 m [19 ft] deep.
c. **Original Porosity (\(e_0\)):**
- Determine \(e_0\) based on the original porosity of the clay.
d. **Settlement Calculation:**
- Calculate how much settlement will occur in the clay.
**Exercise Figure 7.4: Explanation:**
The figure provides a cross-sectional view with the following layers:
- **0 to 5 ft:** Sand, dry unit weight \(\gamma_d = 105 \, \text{lb/ft}^3\)
- **5 to 16 ft:** Silty sand, saturated unit weight \(\gamma_{\text{sat}} = 127 \, \text{lb/ft}^3\), Groundwater Table (GWT) indicated at 5 ft
- **16 to 22 ft:** Clay, saturated unit weight \(\gamma_{\text{sat}} = 121 \, \text{lb/ft}^3\), with noted porosity (\(n = 0.629\)) and a compression index (\(C_c = 0.82\))
- **Load:** A point load of 125 tons is applied at the surface.
This setup is used to analyze the stress changes and resulting settlement in the clay layer.
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