Considering the system of forces shown below: 28 N 125 N.m 26 N 40 34 N 42 N 10 1 m' Determine the perpendicular distance from the origin O to the line of action of the resultant force of the system. O 4.79 m O 6.06 m O 7.82 m O 13.88 m

Q: Q2/ Determine the resultant moment of the forces about point I F=400N 100 N D 30 A B C 45°

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Q: 1. Calculate the resultant of the system of forces shown. 20 kN y 30° 45° 8 kN 4 kN

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Q: THIS IS DYNAMICS OF RIGID BODIES

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Q: 3. In the figure below, what is the moment that this force exerts about point A? F = 400N * 60 C 30…

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Q: Determine the work of the force when it displaces 5m as shown in the figure. 100 N

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Q: QI/ Find the moment about 0 and its direction 31 45 55 N 36 42 N

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Q: 75 N 100 N 20 W- 50 50 N 30 40 120 N 259 80 N 90 N

A: Free body diagram -

Q: Calculate the resultant of this system of forces. Enter your answer with 2 significant figures for…

A: Resultant :R=-5-3+8-12+2=0R=-10kips↓

Q: For the system of forces shown, determine the magnitude of the resultant of the force acting on the…

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Q: Consider the system shown in Cauca.11 Figure 4m 6m 1of1 ) Bott Hed Part A Determine the z, y, and a…

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Q: 8 m -4 m +4m+4m 31 E= Constante

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Q: Q2:- Determine the magnitude of the component force F and the Magnitude of the resultant force FR If…

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Q: 15KN 15kN 4 30° 45° 30 PA 25KN F.

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Q: 0 60 ។ rectangular components. 70KN 3 45° 4x 100 KN B) 30 50KN

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Q: Part A Determine the moment of the force Fc about the door hinge at A. Enter the x, y, and z…

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Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.