Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Concept explainers

Current Division Method
The generalized current divider formula is given by the following relation below,
Question
## Problem 3.14 Consider two voltage dividers shown in **Figure 1**. Suppose that \( v = 361 \, \text{V} \). ### Figure Description **Figure 1 of 2:** - The circuit on the left consists of: - A voltage source labeled \( v \). - A series resistor of \( 75 \, \text{k}\Omega \) connected to node \( a \). - Another series resistor of \( 25 \, \text{k}\Omega \) connected to node \( b \). - The circuit on the right consists of: - A series resistor of \( 40 \, \text{k}\Omega \) connected to node \( a' \). - Another series resistor of \( 60 \, \text{k}\Omega \) connected to node \( b' \). **Figure 2 of 2:** - The combined circuit: - A voltage source labeled \( v = 361 \, \text{V} \). - A series resistor of \( 75 \, \text{k}\Omega \). - A series resistor of \( 25 \, \text{k}\Omega \). - A voltage-dependent voltage source with a gain of \( 25,000 \, io \). - Resistors of \( 40 \, \text{k}\Omega \) and \( 60 \, \text{k}\Omega \) connected in series after the voltage-dependent source. ### Explanation These figures illustrate the concept of voltage division using series resistors in a circuit. The second figure introduces a voltage-dependent source, showcasing advanced circuit analysis techniques. The problem requires analyzing these configurations with a given voltage source value to determine various parameters in the circuits.
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Transcribed Image Text:## Problem 3.14 Consider two voltage dividers shown in **Figure 1**. Suppose that \( v = 361 \, \text{V} \). ### Figure Description **Figure 1 of 2:** - The circuit on the left consists of: - A voltage source labeled \( v \). - A series resistor of \( 75 \, \text{k}\Omega \) connected to node \( a \). - Another series resistor of \( 25 \, \text{k}\Omega \) connected to node \( b \). - The circuit on the right consists of: - A series resistor of \( 40 \, \text{k}\Omega \) connected to node \( a' \). - Another series resistor of \( 60 \, \text{k}\Omega \) connected to node \( b' \). **Figure 2 of 2:** - The combined circuit: - A voltage source labeled \( v = 361 \, \text{V} \). - A series resistor of \( 75 \, \text{k}\Omega \). - A series resistor of \( 25 \, \text{k}\Omega \). - A voltage-dependent voltage source with a gain of \( 25,000 \, io \). - Resistors of \( 40 \, \text{k}\Omega \) and \( 60 \, \text{k}\Omega \) connected in series after the voltage-dependent source. ### Explanation These figures illustrate the concept of voltage division using series resistors in a circuit. The second figure introduces a voltage-dependent source, showcasing advanced circuit analysis techniques. The problem requires analyzing these configurations with a given voltage source value to determine various parameters in the circuits.
**Part A** The voltage divider shown to the left in (Figure 1) is loaded with the voltage divider shown to the right in (Figure 1); that is, \( a \) is connected to \( a' \), and \( b \) is connected to \( b' \). Find \( v_0 \). **Express your answer to three significant figures and include the appropriate units.** \( v_0 = \) [Input box for Value] [Input box for Units] [Submit Button] [Request Answer Button] --- **Part B** Now assume the voltage divider to the right is connected to the voltage divider to the left by means of a current-controlled voltage source as shown in (Figure 2). Find \( v_0 \). **Express your answer to three significant figures and include the appropriate units.** \( v_0 = \) [Input box for Value] [Input box for Units] [Submit Button] [Request Answer Button]
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Transcribed Image Text:**Part A** The voltage divider shown to the left in (Figure 1) is loaded with the voltage divider shown to the right in (Figure 1); that is, \( a \) is connected to \( a' \), and \( b \) is connected to \( b' \). Find \( v_0 \). **Express your answer to three significant figures and include the appropriate units.** \( v_0 = \) [Input box for Value] [Input box for Units] [Submit Button] [Request Answer Button] --- **Part B** Now assume the voltage divider to the right is connected to the voltage divider to the left by means of a current-controlled voltage source as shown in (Figure 2). Find \( v_0 \). **Express your answer to three significant figures and include the appropriate units.** \( v_0 = \) [Input box for Value] [Input box for Units] [Submit Button] [Request Answer Button]
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