Consider two genes. The first one is autosomal with dominant allele A and recessive allele a in the population.The second gene is on the X chromosome with dominant allele R and recessive allele r. Recall that the male Y chromosome has no gene alleles.Match the mode of inheritance (MOI) with the sentence that best describes it.

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Pedigree analysis

Can you please not type the answer can you write it on a paper

Practice Pedigree Problem help. I am confused so please show. Label Phenotypes and genotypes as you go about the Pedigree (and whatever else might be required)! Thank you again for your help, these questions confuse me). Hair or fur length in cats is controlled by a single, autosomal gene; the short hair-allele is dominant to the allele for long hair. Hair color is produced by a different gene which is located on the X chromosome. One allele for this sex-linked gene produces yellow, while an alternate allele produces black fur color; individuals which are heterozygous for these alleles are calico or tortiseshell in color. a). If a long-haired, black male is mated with a calico female homozygous for short hair, what kind of kittens will be produced in the F1generation? Give both genotypes and phenotypes; express the genotypes both symbolically and in words.

NAME: Patterns of Inheritance Worksheet 1. True Breeding Parental Cross A homozygous dominant purple flowered plant is crossed with a homozygous recessive white flowered plant. a. What are the genotypes of the parent plants? (Use the Punnett square to determine the outcomes of this cross. Remember to place the gametes along the left side and top of the square. (P=Purple, p=white) b. What is the genotype of all F₁ plants? 1 b. c. What is the phenotype of all F₁ plants? C. d. How many plants out of 4 will produce white flowers? d. a. 2. Monohybrid Cross: The F₁ offspring from the above problem are allowed to self fertilize. a. What are the genotypes of the F₁ parents? a. (Use the Punnett square to determine the outcomes of this cross. Remember to place the gametes along the left side and top of the square.) b. What is the genotype ratio for this cross? c. What is the phenotype ratio for this cross? d. How many plants out of 4 will produces white flowers? d. b. C.

In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f).  A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy?   What is the probability that the first four children born to the couple will be freckled and normal visioned girls?

Imagine this. A couple wants to have a child. However, they both have had Cystic Fibrosis (CF) in their families and so, they want to know if there is a probability of their child inheriting CF. In this couple, if Mom's genotype is AaDD for the Cystic Fibrosis related alleles (as indicated above) and Dad's genotype of Aadd, what would be the phenotypic and genotypic ratios of the children they could have?If any of the children inherit CF, what can you tell about the severity of the disease? Would it be very severe, moderately severe, or not severe?   Be sure to draw a Punnett Square to show how you arrived at the answer.  asap please

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