Consider the time ot = 2n. a) What total energy, W, is stored in the circuit? b) Write the capacitive voltage divider expression for the voltage Vo, and solve for its value.

$$\begin{gathered} (Note: I think there is a typing error in the question and it should be \omega = 2\pi . \\ Then the circuit remains of type AC, also voltage division for capaci\tan ce is usually for AC\hspace{0.17em}circuits. \\ But I will solve the question according to the given data) \end{gathered}$$

Given

$$\begin{gathered} \omega t = 2\pi \\ Therefore the voltage source becomes \\ V = 5* \cos \left(\omega t\right) = 5*1 = 5V \\ Therefore it has a \mathrm{co}ns\tan t 5V supply just like DC source and therefore be considered as DC\hspace{0.17em}souce of 5V \end{gathered}$$

Let

$$\begin{gathered} C_1 = 100pF \\ {C}_2 = 25pF \\ {C}_3 = 40pF \\ {C}_4 = 80pF \end{gathered}$$