Consider the system x + y + bz x+by+4z ax +ay+2z = 2 1 = a In each case, determine all values of a and b which give the indicated number of solutions, if possible. If no such a and b exist, give the reason why not. (b) exactly one solution.

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A: The correct option is (d)Field with two elements.Explanation:Step 1: Step 2: Step 3: Step 4:

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A: (i).   a=4  ;  b=5 (ii).  a=4,b=5         OR                a=4,b=5  .Explanation:Step 1: Step 2:…

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Q: Manuben

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