Consider the system of equations dx г(3 — т — 4у) dt dy у(1 - 3г), taking (r, y) > 0. (a) Write an equation for the (non-zero) vertical (r-)nullcline of this system: (Enter your equation, e.g., y=x.) And for the (non-zero) horizontal (y-)nullcline: (Enter your equation, e.g., y=x.) (Note that there are also nullclines lying along the axes.) (b) What are the equilibrium points for the system? Equilibria = (Enter the points as comma-separated (x.y) pairs, e.g., (1,2), (3,4).)

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A: FINAL ANSWER I have obtained the answers in the below steps.The general solution…

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A: We have,  2x-2y+z=10 , x + y - 4z = -17 , 3x - y +2z = 13

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