Consider the reaction of N2O and O2 described by the chemical reaction below. Determine the equilibrium constant for this reaction by constructing an ICE table, writing the equilibrium constant expression, and solving it. Complete Parts 1-2 before submitting your answer. 2 N2O(g) +3 O2(g) = 4 NO2(g) 2 NEXT > A 1.00 L reaction vessel was filled with 0.0560 mol O2 and 0.200 mol N2O and allowed to react at 298 K. At equilibrium, there were 0.0200 mol of NO2 present. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) 2N₂O(g) 302(g) 10 4NO2(g) RESET 0.0560 0.200 -1.00 -0.0560 0.0200 -0.0200 0.0100 -0.0100 -0.0050 0.0050 0.0150 -0.0150 0.210 0.190 0.0410 0.0710 0.0360 0.180

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
Consider the reaction of N2O and O2 described by the chemical reaction below.
Determine the equilibrium constant for this reaction by constructing an ICE table,
writing the equilibrium constant expression, and solving it. Complete Parts 1-2
before submitting your answer.
2 N2O(g) +3 O2(g) = 4 NO2(g)
SH
2
NEXT >
A 1.00 L reaction vessel was filled with 0.0560 mol O2 and 0.200 mol N2O and allowed to react
at 298 K. At equilibrium, there were 0.0200 mol of NO2 present. Fill in the ICE table with the
appropriate value for each involved species to determine concentrations of all reactants and
products.
Initial (M)
Change (M)
Equilibrium (M)
2N₂O(g)
302(g)
==
4NO2(g)
RESET
0
0.0560
0.200
-1.00
-0.0560
0.0200
-0.0200
0.0100
-0.0100
-0.0050
0.0050
0.0150
-0.0150
0.210
0.190
0.0410
0.0710
0.0360
0.180
OOD
MacBook Air
ུཥ
AA
DII
DD
F8
F9
D
F10
F11
E
Transcribed Image Text:Consider the reaction of N2O and O2 described by the chemical reaction below. Determine the equilibrium constant for this reaction by constructing an ICE table, writing the equilibrium constant expression, and solving it. Complete Parts 1-2 before submitting your answer. 2 N2O(g) +3 O2(g) = 4 NO2(g) SH 2 NEXT > A 1.00 L reaction vessel was filled with 0.0560 mol O2 and 0.200 mol N2O and allowed to react at 298 K. At equilibrium, there were 0.0200 mol of NO2 present. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) 2N₂O(g) 302(g) == 4NO2(g) RESET 0 0.0560 0.200 -1.00 -0.0560 0.0200 -0.0200 0.0100 -0.0100 -0.0050 0.0050 0.0150 -0.0150 0.210 0.190 0.0410 0.0710 0.0360 0.180 OOD MacBook Air ུཥ AA DII DD F8 F9 D F10 F11 E
Consider the reaction of N2O and O2 described by the chemical reaction below.
Determine the equilibrium constant for this reaction by constructing an ICE table,
writing the equilibrium constant expression, and solving it. Complete Parts 1-2
before submitting your answer.
2 N2O(g) +3 O2(g) = 4 NO2(g)
<
PREV
1
2
Based on the data from your ICE table, construct the expression for Kc. Each reaction participant
must be represented by one tile. Do not combine terms.
Once the expression is constructed, solve for Kc.
Kc
=
RESET
[0.200]
[0.0560]
[0.0200]
[0.190]
[0.0410]
[0.0710]
[0.0360]
[0.180]
[0.200]²
[0.0560]³
[0.0200]⭑
[0.190]²
[0.0410]³
[0.0710]³
[0.0360]³
[0.180]
0.0643
2.57
15.6
0.390
MacBook Air
Transcribed Image Text:Consider the reaction of N2O and O2 described by the chemical reaction below. Determine the equilibrium constant for this reaction by constructing an ICE table, writing the equilibrium constant expression, and solving it. Complete Parts 1-2 before submitting your answer. 2 N2O(g) +3 O2(g) = 4 NO2(g) < PREV 1 2 Based on the data from your ICE table, construct the expression for Kc. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Kc. Kc = RESET [0.200] [0.0560] [0.0200] [0.190] [0.0410] [0.0710] [0.0360] [0.180] [0.200]² [0.0560]³ [0.0200]⭑ [0.190]² [0.0410]³ [0.0710]³ [0.0360]³ [0.180] 0.0643 2.57 15.6 0.390 MacBook Air
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 5 steps with 9 images

Blurred answer
Knowledge Booster
Chemical Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY