Consider the reaction of 30.0 mL of 0.244 M Bal, with 20.0 mL of 0.315 M Na PO4. 3 Bal2(aq) + 2 Na;PO4(aq) → Ba3(PO4)2(s) + 6 Nal(aq) If you have 0.00732 moles of Bal2, What quantity in moles of precipitate are produced if all the Bal2 were consumed based on the balanced chemical equation?

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**Chemical Reaction Problem**

Consider the reaction of 30.0 mL of 0.244 M BaI₂ with 20.0 mL of 0.315 M Na₃PO₄.

**Balanced Chemical Equation:**
3 BaI₂(aq) + 2 Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6 NaI(aq)

If you have 0.00732 moles of BaI₂, calculate the quantity in moles of precipitate produced if all BaI₂ is consumed based on the balanced chemical equation.

**Interaction Area:**
There is a keypad and input area to enter the number of moles of the precipitate: 
- Input field labeled "mol"
- Number pad with numbers 0-9 and additional buttons for decimal, plus/minus, clear, and an exponential notation (×10). 

**Note:**
Ensure your calculations take into consideration the stoichiometry of the reaction as per the balanced equation.
Transcribed Image Text:**Chemical Reaction Problem** Consider the reaction of 30.0 mL of 0.244 M BaI₂ with 20.0 mL of 0.315 M Na₃PO₄. **Balanced Chemical Equation:** 3 BaI₂(aq) + 2 Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6 NaI(aq) If you have 0.00732 moles of BaI₂, calculate the quantity in moles of precipitate produced if all BaI₂ is consumed based on the balanced chemical equation. **Interaction Area:** There is a keypad and input area to enter the number of moles of the precipitate: - Input field labeled "mol" - Number pad with numbers 0-9 and additional buttons for decimal, plus/minus, clear, and an exponential notation (×10). **Note:** Ensure your calculations take into consideration the stoichiometry of the reaction as per the balanced equation.
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