Consider the reaction: NH₂Cl (s) → NH₂ (g) + HCl (g) 3 -1 AS = 85.7 J K ¹mol™¹, AH = 175.96 kJ/mol 9 3 d) A gas mixture of total pressure 56 kPa consisting of 1 part NH₂ to 1 part HCl was obtained in the reaction above. Calculate the partial pressure of NH3 and HCl gas in the gas mixture. e) How much work is done when a piston is compressed from 9.87 L to 2.56 L under constant atmospheric pressure (1.013 × 10³ Pa)? f) What intermolecular forces will be dominant between NH₂ molecules?

[obj 13] Plz help with question #5, part B, and show work.

Consider the following reaction where Kc = 1.80×10-4 at 298 K.NH4HS(s) NH3(g) + H2S(g)A reaction mixture was found to contain 5.52×10-2 moles of NH4HS(s), 1.77×10-2 moles of NH3(g), and 1.34×10-2 moles of H2S(g), in a 1.00 liter container.Is the reaction at equilibrium?If not, what direction must it run in order to reach equilibrium?The reaction quotient, Qc, equals .The reactionA. must run in the forward direction to reach equilibrium.B. must run in the reverse direction to reach equilibrium.C. is at equilibrium.

Pls help ASAP

35 Consider the equilibrium system described by the chemical reaction below, which has a value of Kc equal to 3.01 × 10³ at 900 K. If an initial mixture of 0.0216 mol SO2 and 0.0148 mol O2 reacts in a 1.0 L vessel, what will be the concentration of SO3 at equilibrium? 2 SO:(g) + O2(g)= 2 SO:(g) 1 3 NEXT Based on the given values, set up ICE table in order to determine the unknown. 2 SO:(g) O:(g) + 2 SO:(g) Initial (M) 0.0216 0.0148 Change (M) 0.0216 - 2x 0.0148 - x Equilibrium (M) 5 RESET 0.0216 0.0148 1.0 +x +2x -2x 0.0216 + x 0.0216 + 2x 0.0216 - x 0.0216 - 2x 0.0148 + x 0.0148 + 2x 0.0148 - x 0.0148 - 2x

10 Please help me with the brief solution and answer, thank you

Part A The reaction below is carried out at a different temperature at which Ke = 0.055. This time, however, the reaction mixture starts with only the product, NO = 0.0100 M, and no reactants. Find the equilibrium concentrations of N2, O2, and NO at equilibrium. N2(8) + O2(g) = 2NO(g) Express your answers to three significant figures separated by commas. > View Available Hint(s) ? [N2]. [O2]. [NO] = М, М, М Submit Provide Feedback Next >

Consider the following reaction where Kc = 1.20×10-2 at 500 K:PCl5 (g)  PCl3 (g) + Cl2 (g)A reaction mixture was found to contain 0.115 moles of PCl5 (g), 4.47×10-2 moles of PCl3 (g), and 4.16×10-2 moles of Cl2 (g), in a 1.00 liter container.Indicate True (T) or False (F) for each of the following:    1. In order to reach equilibrium PCl5(g) must be consumed .    2. In order to reach equilibrium Kc must increase .    3. In order to reach equilibrium PCl3 must be consumed .    4. Qc is less than Kc.    5. The reaction is at equilibrium. No further reaction will occur.

Consider the following reaction where Kc = 1.29×10-² at 600 K: ? COCI₂ (9) co (g) + Cl₂ (9) A reaction mixture was found to contain 0.107 moles of COCI₂ (g), 5.31×10-² moles of CO (g), and 3.63×10-² moles of Cl₂ (g), in a 1.00 liter container. Indicate True (T) or False (F) for each of the following: F 1. In order to reach equilibrium COCI₂(g) must be produced. 2. In order to reach equilibrium K must decrease . 3. In order to reach equilibrium CO must be produced. Ⓒ 4. Qc is less than Kc. Ⓒ 5. The reaction is at equilibrium. No further reaction will occur.

Use arrows (up / down) to indicate the affect of each of these disturbances (stresses) on the concentration of the reactants and products in this equilibrium: 9 KJ + 2 S02 9) + 02 (9) = 2 S03 (9A disturbance affect on affect on affect on ISO2] [02] ISO3] decrease [SO2] increase [02] increase [SO3] increase pressure decrease temp Period 4 CHE