Consider the reaction at 25 degrees celsius 2NO3-(aq)+8H+(aq)+3Cu(s)=3Cu2+(aq)+2NO(g)+4H2O(l) At what pH is the reaction at equilibrium with all other ionic species at 0.01M and gases at 1 atm?

BaCl, · H,O(s) loses water when it is heated in an oven: BaCl, · H,O(s) = BaCl, (s) + H,O(g) AH° = 63.11 kJ/mol at 25 °C AS +148 J/(K · mol) at 25 °C Write the equilibrium constant for this reaction. Find the vapor pressure of H,O (PH,0) above BaCl, · H,O(s) at 298 K. PH,0 bar = If AH° and AS° are not temperature dependent (a poor assumption), estimate the temperature at which PH,0 above BaCl, · H, O(s) will be 1 bar. T = °C

For the nitrogen fixation reaction 3H2(g) + N2(g)  2NH3(g), at 500°C. If 0.250 M H2 and 0.050 M NH3 and 2.7 M N2 are present at equilibrium, what is the value of equilibrium constant?

Given the two reactions 1. H 2 S(aq)⇌HS − (aq)+H + (aq), K 1 = 9.29×10−8, and2. HS − (aq)⇌S 2− (aq)+H + (aq), K 2= 1.48×10−19,what is the equilibrium constant K final for the following reaction?S 2− (aq)+2H + (aq)⇌H 2 S(aq)

If the equilibrium constant of a given reaction is 2.10, what is the equilibrium constant of its reverse reaction?

the equilibrium constant for the authorization of water at 25°C is 1.00 X 10^-14 H2O----->H+(aq)+OH-(aq) The DH° is 55.8 kJ/mol. Determine the equilibrium constant at 38.2 °C

Benzoic acid (C,H,COOH) dissolves in water to the extent of 2.00 g L¯1 at 15°C and in diethyl ether to the extent of 6.6 × 10² g L¯1 at the same temperature. (a) Calculate the equilibrium constants at 15°C for the two reactions C,H;COOH(s) 2 C,H;COOH(aq)

The equilibrium constant for the chemical equation N,(g) + 3 H, (g) 2 NH,(g) is K, 0.356 at 197 °C. Calculate the value of the K, for the reaction at 197 °C. K.

Use the data in the supporting materials to calculate the equilibrium constant (Kp) for the following reaction at 25°C. 2 SO2(g) + O2(g) =2 S03(g) Кра 4.24e24 Calculate Kp for the reaction at 49°C using the following equations. (a) the van't Hoff equation below. (P), A,H° RT? a In K Кр = 1.138e22 (b) the Gibbs-Helmholtz equations below to find A-G° at 49°C and hence, Kp at the same temperature. AG ΔΗ (i) = - T2 A-G2 A;G1 1 (ii) T2 T1 T1 Kp = 1.138e22 (c) A-G° = ArH° – TA¡S° to find A-G° at 49°C and hence, Kp at the same temperature. Кр 3D 1.7742е22 State the approximations employed in each case. The assumption that A,H° is temperature independent and equal to the value calculated at 298.15 K is required by all three parts A second assumption that AS° is temperature independent and equal to the value calculated at 298.15 K is required by part (c) Compare your results. The answers calculated in parts (a) and (b) ▼ in part (c) are very close as expected because the formulas used to…