Question 18 (Ch.7)
Consider the problem below:
(Equation 1) 2 H2O(l) ---> 2 H2(g) + O2(g) ΔH = 571.6 kJ
(Equation 2) N2O5(g) + H2O(l) ---> 2 HNO3(l) ΔH = -73.7 kJ
(Equation 3) 2 H2(g) + 6 O2(g) + 2 N2(g) ---> 4 HNO3(l) ΔH = -696.4 kJ
(Equation 4) 2 N2(g) + 5 O2(g) ---> 2 N2O5(g) ΔH = ???????
To find ΔH for equation 4 you must:
Question 18 options:
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