Consider the pipe shown in (Figure 1). The force F has a magnitude of 800 N and coordinate direction angles of a = 60°,8=120°, y = 45°. Figure 1 of 1 > -0.5 m- F 0.4 m + 0.3 m Part A Determine the moment f force F about point O. Express the result as a Cartesian vector. Express your answer in terms of the unit vectors i, j, and k. Use the 'vec' button to denote vectors in your answers. Express your answer using three significant figures. AΣo↓↑vec 3 ? Mo = N.m Submit Provide Feedback Next > Request Answer

Part C - Moment due to two forces As shown, a member is fixed at the origin, point O, and has two applied forces, F₁ and F2, applied at the free end, point B. (Figure 3) The forces are given by F₁ = 90 Ni-120 Nj+65 Nk and F2 has magnitude 165 N and direction angles = = 158.0°, B=77.0°, and y = 72.6°. The dimensions are x₁ = 4.00 m, y₁ = 5.90 m, and z₁ = 2.90 m. What is the moment about the origin due to the applied forces? Express the individual components of the Cartesian vector to three significant figures, separated by commas. ► View Available Hint(s) Mo =[ Submit 15. ΑΣΦ | 11 vec p ? i, j, k] N.m

A 65 kg person running at 2.0 m/s jumps onto the skim board at right. The skim board is 50 cm wide and 120 cm long, with an area of 0.60 m². Part A Draw a sketch of this situation. Part B If the person jumps onto the board on sand with a coefficient of friction of f=0.50, what force will resist the forward movement of the board [N]? Recall the friction force is the normal force times the coefficient of friction. Part C Now assume the person jumps onto the board on a 0.50 cm film of fresh water at 30°C. Use Newton's law of viscosity to estimate the force resisting the forward movement of the board.

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The class I'm taking is physics for scientists and engineers! I am completely stuck. Need help. I have attached the problem. Please view  attachment before answering. If you can please explain your answer so I can fully understand. Thank you so much!

A body of mass m and negligible size starts from rest and slides down the surface of a frictionless solid sphere of radius R R, as shown below.

On a very muddy football field, a player of mass m₁ tackles a second one of mass m2 = 3m₁/2. Immediately before the collision, player 1 is slipping with a velocity of v₁ due north and player 2 is sliding with a velocity of v2 = 2v1 due east. 3a. Sketch the situation, placing careful labels, and write formulae for the initial momenta of the two players. Might want to chose a coordinate system that will help you figure out how to add together these momenta. 3b. What is the magnitude of the total momentum of the system of these two players before they collide? 3c. What are the magnitude and direction of the velocity at which the two players move together immediately after the collision? 3d. Calculate the loss of kinetic energy associated with this collision.

Pls help with the following and explain the right answer, thank you. part B. Find the direction of this force as the angle measured counterclockwise from the +x+�-axis directed horizontally to the right. Express your answer in degrees.

A narrow uniform rod has length 2a. The linear mass density of the rod is p. so the mass m of a length of the rod is pl. Part A A point mass is located a perpendicular distance from the center of the rod. Calculate the magnitude of the force that the rod exerts on the point mass. (Hint: Let the rod be along the y-axis with the center of the rod at the origin, and divide the rod into infinitesimal segments that have length dy and that are located at coordinate y. The mass of the segment is dm = pdy. Write expressions for the I- and y-components of the force on the point mass, and integrate from a toa to find the components of the total force). Express your answer in terms of the gravitational constant G and some or all of the variables m, p, a, and r. IVE ΑΣΦ ? a xa Xb √x xx x b IXI F= Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining The correct answer does not depend on: la Part B n(n+1)2 + n(n−1)(n−2) 1+nz+ T³ +... (|1| < 1).) What does your result…

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