College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An object is released from rest and falls in free fall motion. The speed v of the object after it has fallen a distance y is given by v2 = 2gy. In an experiment, v and y are measured and the measured values are used to calculate g. If the percent uncertainty in the measured value of v is 5.19% and the percent uncertainty in the measured value of y is 5.00%, what is the percent uncertainty in the calculated value of g?arrow_forwardGiven that A + B = x₁Î + Y₁Ĵ and Ö Ē = x₂Î + y₂), what is ? A ® B = ²/² ( x ₁ + x₂) ₁ + 1/{ (Y₁ +92)ĵ B Î D B = ½ (×₁ − ×₂) Î + ½ (Y₁ −³₂)Î E B = ½¼½ (X₁ − ×₂)Î + ½ (Y₁ + Y2 )Ĵ ³ = ½ (X₁ + X₂) Î + ½ (Y₁ −Y₂)ĵ B = ½ (³₁ −³₂)ĵarrow_forwardThe functions ¢1(x) and ø2(x) are normalized: d φ( (α) φι(α) dx 0(x) 62(x) = 1 = 1 -00 -00 and are mutually orthogonal dx oi(x) $2(x) dx 4i(x) $1(x) = 0 . Is the function b_(x) = ¢1(x) – $2(x) normalized? If not, determine its normalization constant and write the formula for the normalized y_ (x). Is the function +(x) = ¢1(x) + ¢2(x) %3D orthogonal to _(x)?arrow_forward
- Instrument Ruler Quantities Diameter Units m Meas #1 Meas #2 Meas #3 Meas #4 Meas #5 Meas #6 0.011 0.017 0.019 0.016 0.009 0.021 Vernier Caliper Micro-meter Diameter Diameter 0.0120 0.0166 0.0182 0.0151 0.0100 0.0225 0.01268 0.01745 0.01904 0.01587 0.00947 0.02221 Ruler Volume 7.0E-07 2.6E-06 3.6E-06 2.1E-06 4.E-07 4.8E-06 Measurements: diameter and volume. Results: mass Vernier Caliper Volume Measurements: diameter and mass. Results: volume O Measurements: diameter and mass. Results: none. 9.05E-07 2.40E-06 3.16E-06 1.80E-06 5.24E-07 5.96E-06 Among this data, what is considered raw measurement and plain result? Micro-meter Volume 1.067E-06 2.782E-06 3.614E-06 2.093E-06 4.45E-07 5.736E-06 Measurements: diameter measured with the ruler only and mass. Results: volume. Scale Mass kg 0.00850 0.02080 0.02720 0.01680 0.00389 0.04423arrow_forward..................... The dimensions of the quantity kinetic energy, designated by K, are kg m/s, It can be written in terms of the momentum p and mass m as K = 2m (a) What are the units of momentum in terms of fundamental SI units? (Use the following as necessary: kg, m, and s.) [P) - (b) Force is measure in units of newtons, N, where 1N- 1 kg m/s. What are the units of momentum p in terms of a newton and another fundamental SI unit? (Use the. following as necessary: N, m, and s.) [P) = (c) What If? Physicists often measure the momentum of subatomic particles moving near the speed of light in units of MeV/c, where c is the speed of light, and 1 Mev = 1.6 x 101 kg m/s. Based on this, what are the units of momentum for a high-speed subatomic particle in terms of fundamental SI units? What are the units of momentum for a high-speed subatomic particle in terms of a newton and another fundamental SI unit? [P] -arrow_forwardConsider the physical quantities m, s, v, a, t, and r with dimensions [m] = M, [s] = L, [v] = LT–1, [a] = LT–2, [t] = T, and [r] = L. Assuming each of the following equations is dimensionally consistent, find the dimension of the quantity on the left-hand side of the equation: (a) F = ma; (b) K = 0.5mv2; (c) p = mv; (d) W = mas; (e) L = mvr.arrow_forward
- Consider the physical quantities s, v, a, m, and t with dimensions [s] = L, [v] = LT-¹, [a] = LT-2, [m] = M, and [t] = T. Select the dimensionally consistent equation(s). U √2as = v S = vtm + a = U S = at at² marrow_forwardP is pressure, x distance and v velocity. What are the units of k so that the equation v = K dP/dx is dimensionally correct? (A) m/s (B) m^3s / kg (C) kg / (m s^3) D) k has no unitsarrow_forwardI need help with a University Physics 1 (significant figures) - The problem is described in the image below:arrow_forward
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