Consider the molecule of acrylaldehyde. Its Lewis structure is shown. H يلول H sp What is the hybridization state of each of the carbon atoms in acrylaldehyde? sp² H sp³ H sp4 Ⓒsp³ d²

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### Acrylaldehyde Molecule and Hybridization

**Consider the molecule of acrylaldehyde. Its Lewis structure is shown below:**

The Lewis structure of acrylaldehyde is depicted with carbon (C), hydrogen (H), and oxygen (O) atoms. It illustrates the following bonds:

- Two carbon atoms are connected by a double bond.
- Each carbon atom has bonds with hydrogen atoms.
- One carbon is also double-bonded to an oxygen atom, which carries two lone pairs.

**Hybridization State**

**Question:** What is the hybridization state of each of the carbon atoms in acrylaldehyde?

**Options:**
- ○ sp
- ○ sp²
- ○ sp³
- ○ sp⁴
- ○ sp³d²

### Explanation of Lewis Structure

- The carbon atoms form double bonds and single bonds. Each carbon participates in three sigma bonds: two with hydrogen and one with another carbon or oxygen. 
- The double bonds indicate sp² hybridization because each carbon forms three sigma bonds and one pi bond.
  
**Conclusion:** The correct hybridization for both carbon atoms in acrylaldehyde is **sp²**.
Transcribed Image Text:### Acrylaldehyde Molecule and Hybridization **Consider the molecule of acrylaldehyde. Its Lewis structure is shown below:** The Lewis structure of acrylaldehyde is depicted with carbon (C), hydrogen (H), and oxygen (O) atoms. It illustrates the following bonds: - Two carbon atoms are connected by a double bond. - Each carbon atom has bonds with hydrogen atoms. - One carbon is also double-bonded to an oxygen atom, which carries two lone pairs. **Hybridization State** **Question:** What is the hybridization state of each of the carbon atoms in acrylaldehyde? **Options:** - ○ sp - ○ sp² - ○ sp³ - ○ sp⁴ - ○ sp³d² ### Explanation of Lewis Structure - The carbon atoms form double bonds and single bonds. Each carbon participates in three sigma bonds: two with hydrogen and one with another carbon or oxygen. - The double bonds indicate sp² hybridization because each carbon forms three sigma bonds and one pi bond. **Conclusion:** The correct hybridization for both carbon atoms in acrylaldehyde is **sp²**.
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